1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To find the number of moles of CO2 in 22g, you first need to calculate the molar mass of CO2 (44.01 g/mol). Then, divide the given mass (22g) by the molar mass to get the number of moles. Therefore, 22g of CO2 is equal to 0.50 moles.
To determine the grams of CO2 produced from 2.5 moles of O2, we first need to consider the balanced chemical equation for the combustion of a hydrocarbon (e.g., methane): CH4 + 2O2 → CO2 + 2H2O. From this equation, 2 moles of O2 produce 1 mole of CO2. Therefore, 2.5 moles of O2 would produce 1.25 moles of CO2. Since the molar mass of CO2 is approximately 44 grams/mol, 1.25 moles of CO2 corresponds to 55 grams (1.25 moles × 44 g/mol).
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1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
44.0095
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To find the number of moles of CO2 in 22g, you first need to calculate the molar mass of CO2 (44.01 g/mol). Then, divide the given mass (22g) by the molar mass to get the number of moles. Therefore, 22g of CO2 is equal to 0.50 moles.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
The answer is 4,1 CO2 moles.
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.