1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
To convert molecules to moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, to find the number of moles in 8.50 molecules of sodium sulfate, you calculate ( \frac{8.50 \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} ), which gives approximately (1.41 \times 10^{-23}) moles of sodium sulfate.
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
To convert molecules to moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, to find the number of moles in 8.50 molecules of sodium sulfate, you calculate ( \frac{8.50 \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} ), which gives approximately (1.41 \times 10^{-23}) moles of sodium sulfate.
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
For sodium sulfate decahydrate (Na2SO4·10H2O), on heating, 10 moles of water molecules will be driven off per mole of the hydrate. Each formula unit of the hydrate contains 10 water molecules.
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
c- 6. When sodium sulfate dissolves in water, it dissociates into three ions: two sodium ions (Na+) and one sulfate ion (SO4^(2-)). Therefore, 2 moles of sodium sulfate will produce a total of 6 moles of ions in solution.
To find the number of moles of sodium sulfate in 0.1000g of the compound, you first need to determine the molar mass of Na2SO4. Then, divide the given mass by the molar mass to get the moles.
The reaction requires 2 moles of hydrogen gas and 1 mole of oxygen gas to produce 2 moles of water.
4.5 moles
There are (5.24 \times 10^{22}) molecules of sodium acetate in 0.87 moles of sodium acetate. This is calculated by multiplying Avogadro's number (6.022 x 10^23 molecules/mol) by the number of moles given (0.87 mol).
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
There are 2 moles of sodium ions in 1 mole of sodium sulfate (Na2SO4). Therefore, in 0.482 moles of sodium sulfate, there would be 0.482 x 2 = 0.964 moles of sodium ions. Finally, multiplying by Avogadro's number (6.022 x 10^23) gives approximately 5.80 x 10^23 sodium ions.