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How is molar mass determined using colligative properties?
You can calculate the molecular mass using freezing point depression or boiling point elevation using the formula: mols solute= change in BP (or FP) x kg solvent / Kb (or Kf) /i Where Kb and Kf are constants and i is number of ions (or 1 if covalent) Then take mols solute (calculated) and divide into grams solute (recorded)
What is the molar mass of adrenaline in a solution of 0.64 g of adrenaline in 36.0 g of CCl4 elevates the boiling point by 0.49?
First, calculate the molality of the adrenaline solution in CCl4 using the elevation in boiling point. Then, determine the moles of adrenaline in the solution using the molality and mass of CCl4. Finally, divide the mass of adrenaline by the moles to find the molar mass.
What is the molar mass of haemocyanin and the freezing point of the solution when an aqueous solution is prepared by dissolving 1.5 grams of haemocyanin a protein obtained from crabs in 0.25 litres of?
Haemocyanins are a group of proteins.
What is the gram fromula mass of CaCl2?
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
What is the change in the boiling point and freezing point of 500 grams of water if 45 grams of glucose C6H12O6 were dissolved in it?
This quantity is equivalent to 90 g glucose / kg water = 0.50 mole particles of solute / kg water, so with a 'molar cryoscopic constant' for water of -1.86 oC/kgthis lowers the freezing point to -0.93 oC.
What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.
What mass of CaCL2 is needed to prepare 2.850 L of a 1.56 M solution?
To find the mass of CaCl2 needed, you need to use the formula: Mass = molarity × volume × molar mass. First, calculate the number of moles of CaCl2 using the molarity and volume. Then, multiply the moles by the molar mass of CaCl2 (110.98 g/mol) to find the mass needed. A 1.56 M solution means it contains 1.56 moles of CaCl2 in 1 liter of solution.
How can the freezing point depression method be used to calculate the molar mass of a solute in a solution?
The freezing point depression method can be used to calculate the molar mass of a solute in a solution by measuring the decrease in the freezing point of the solvent when the solute is added. By knowing the freezing point depression constant of the solvent and the amount of solute added, the molar mass of the solute can be calculated using the formula: molar mass (freezing point depression constant molality) / freezing point depression.
What is the molar weight of CaCl2?
The molar mass of CaCN2 = 80.1021 g/mol
How would you make 1 liter of a 1 molar solution of CaCl2?
To make 1 liter of a 1 molar solution of CaCl2, you would need to dissolve 147.02 grams of CaCl2 in enough water to make a final volume of 1 liter. This formula weight comes from the atomic weights of calcium (40.08 g/mol) and chlorine (35.45 g/mol).
What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
Molarity of CL in 110 ml of a solution containing 5.55g of CaCl2?
To find the molarity of Cl in the solution, first calculate the number of moles of CaCl2 using its molar mass. Then, since each formula unit of CaCl2 contains 2 moles of Cl, multiply the moles of CaCl2 by 2 to get moles of Cl. Finally, divide moles of Cl by the volume of the solution in liters to find the molarity.
What is the mass of 0.89 mol of CaCl2?
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
What is boiling point of 1 molar urea solution?
The boiling point of a 1 molar urea solution will be higher than the boiling point of pure water. Urea is a non-volatile solute that raises the boiling point of the solution through boiling point elevation. The exact boiling point elevation can be calculated using the formula: ΔTb = i * K_b * m, where i is the van't Hoff factor (1 for urea), K_b is the ebullioscopic constant of the solvent (water), and m is the molality of the solution.
7.5 grams of CaCl2 is how many moles?
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
How can one find the molality of a solution given its freezing point?
To find the molality of a solution given its freezing point, you can use the formula: molality (Kf Tf) / molar mass of solvent. Here, Kf is the freezing point depression constant of the solvent, Tf is the freezing point depression, and the molar mass of the solvent is the mass of one mole of the solvent. By plugging in these values, you can calculate the molality of the solution.
How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
