2NaI refers to the compound sodium iodide. Sodium iodide is commonly used in medicine, as a source of iodine in chemical processes, and in Photography.
When sodium metal is combined with iodine gas, an oxidation-reduction reaction occurs. Sodium loses and electron to form the sodium cation, and iodide gains an electron to form iodide. The resulting compound is NaI.
Standardization of sodium thiosulfate uses potassium iodate with excess potassium iodide and acidified. Iodine is liberated and that is titrated with sodium thiosulfate. KIO3 + 5KI + 3H2SO4 -----> 3K2SO4 + 3H2O + 3 I2 I2 + 2Na2S2O3 -------> 2NaI + Na2S4O6 So 1 mole of KIO3 produces 3 moles of Iodine. 1 moles of iodine reacts with 2 moles of thiosulfate. So 6 moles of sodium thiosulfate react with 1 mole of potassium iodate KIO3.
Another name for gold is "aurum," which is its Latin name.
I think you meant a scientific name. A scientific name is the two-part name used to refer to a species. For example:Homo sapiens is the scientific name of the human species.Felis catus is the scientific name of the housecat species.Loxodonta africana is the scientific name of the African elephant species.Quercus alba is the scientific name of the white oak species.
Isaac is his first name. He had no middle name.
2Na + I2 ==> 2NaI
Cl2 + 2NaI --> 2NaCl + I2
2Na + I2 --> 2NaI
4
Cl2(g) + 2NaI(s) --------> 2NaCl(s) + I2(s)
2NaI(aq)+Br2(l)-->2NaBr(aq)+I2(l) Sodium iodide+bromine-->sodium bromide+iodine
the equation for sodium nitrate and copper III iodide can be given below.Cu I 2 +2 Na No3 ->I (NO3)2 + 2NaI. this is the balance reaction for the above.
The symbol "Na" typically refers to the element sodium, atomic number 11.
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
The balanced chemical equation for the reaction between Br₂ and NaI is: Br₂ + 2NaI -> 2NaBr + I₂ In this reaction, two moles of sodium iodide (NaI) react with one mole of bromine (Br₂) to form two moles of sodium bromide (NaBr) and one mole of iodine (I₂).
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
2Na2S2O3 + I2 --> 2NaI + Na2S4O6