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What is the molarity of a solution consisting of 0.250 mol NaCl dissolved in 2.25 L of solution?

The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M


What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?

To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.


Molarity of a solution of 6 moles mol of NaCl in 2L water?

Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========


What would be the molarity of a 5 percent NaCl solution?

To calculate the molarity of a 5% NaCl solution, you need to know the density of the solution. Once you have the density, you can convert the percentage to grams per liter. Then, using the molar mass of NaCl (58.44 g/mol), you can calculate the molarity using the formula Molarity = (mass of solute in g) / (molar mass of solute in g/mol) / (volume of solution in L).


How do you calculate the molarity of the solution of 17.52 grams of Na Cl in a total volume of 2000 ml of solution?

Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------


A sample of 76g of NaCl is dissolved to make 1L of solution. what is the molarity of the solution?

1.3g


Equal moles of H2O and NaCl are present in a solution Hence molarity of NaCl is?

I suppose that this situation is not possible.


What is the molarity of a 3.292 Liter solution that is made from 17.62 grams of NaCl?

A liter is equal to a dm3. So, we have 3,292 dm3 solution. We need the amount of the NaCl. It is m/M -> 17,62 / 58,5 -> approx. 0,3012 mol. So, the molarity is 0,3012 / 3,292 -> 0,0915 mol dm-3 .


What is the molarity of a 3000 liters solution containing 300 grams of NaCl?

Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------


What is the concentration M of a NaCl solution prepared by dissolving 3.8 g of NaCl in sufficient water to give 245 mL of solution?

Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------


What is the molarity of a 2.0-liter solution containing 58 grams of NaCl?

To calculate the molarity, you first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is approximately 58.5 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters to get the molarity. In this case, molarity = (58 grams / 58.5 g/mol) / 2.0 L.


What would you be need to do to calculate the molarity of 10 mol of NaCl in 200?

To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.