For this you need the Atomic Mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.
82.5 moles Fe / (55.9 grams) = 1.48 moles Fe
The answer is 125,65 g.
The balanced chemical equation for the reaction between Fe3O4 and H2 is: Fe3O4 + 4H2 -> 3Fe + 4H2O From the equation, it can be seen that 1 mole of Fe3O4 reacts with 4 moles of H2. Calculate the moles of H2 in 300g, then use the mole ratio to find the moles of Fe3O4 needed. Finally, convert the moles of Fe3O4 to grams using its molar mass to determine the amount required.
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams454 grams CO2 / (44.0 grams) = 10.3 moles CO2
To find the number of moles in 1.1 grams of FeCl3, you'll first determine the molar mass of FeCl3 (55.85 + 35.45*3) = 162.31 g/mol. Then, divide the given mass (1.1g) by the molar mass to get the number of moles (1.1g / 162.31g/mol ≈ 0.007 moles of FeCl3).
To find the number of moles of CaBr2 in 5.0 grams, you first need to calculate the molar mass of CaBr2. The molar mass of CaBr2 is 200.8 g/mol. Divide the given mass by the molar mass to find the number of moles: 5.0 g / 200.8 g/mol = 0.025 moles of CaBr2. Since there is one mole of CaBr2 for every two moles of CaBr, you have half of that amount in moles of CaBr: 0.025 moles / 2 = 0.0125 moles of CaBr.
The molar mass of iron is 55.85 g/mol. To find the weight of 7.4 moles of iron, you would multiply the number of moles by the molar mass. Therefore, 7.4 moles of iron would weigh 7.4 moles * 55.85 g/mol = 411.49 grams.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
To find the number of moles in 1.5 grams of iron, you need to divide the mass of iron by its molar mass. The molar mass of iron is approximately 55.85 g/mol. So, 1.5 grams of iron is equal to 1.5 g / 55.85 g/mol = 0.027 moles of iron.
Let's see. 3 moles gold (197.0 grams/1 mole Au) = 591 grams of gold ----------------------------- 10 mole iron (55.85 grams/1 mole Fe) = 558.5 grams of iron ----------------------------- So, 3 moles of gold has more mass that 10 moles of iron. (heavier)
The molar mass of iron is approximately 55.85 g/mol. Thus, the mass of 4 moles of iron would be 4 moles * 55.85 g/mol = 223.4 grams.
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
To determine the number of moles in 223.2 grams of iron (Fe), you will first need to divide the given mass (223.2 g) by the molar mass of iron, which is approximately 55.85 g/mol. This calculation will give you the number of moles of iron in 223.2 grams.
This cannot be answered because it is essential to know what element you're dealing with here. 8.2 grams of iron will contain considerably less atoms than 8.2 of hydrogen. Therefore, the number of moles in 8.2 grams of iron will differ from the number of moles in 8.2 grams of hydrogen.
To calculate the number of moles in 1.68g of iron, we need to use the molar mass of iron, which is approximately 55.85 g/mol. Divide the mass of iron (1.68g) by its molar mass to find the number of moles present. Therefore, there are approximately 0.03 moles of iron in 1.68g.
To convert moles to grams, you need to multiply by the molar mass of the element. The molar mass of Fe (iron) is approximately 55.85 g/mol. For 24.6 moles of Fe, the mass in grams would be 24.6 moles x 55.85 g/mol = 1373.31 grams (approximately).
825 grams = 825,000 mg. 1 gr. = 1000 mg.
The rusting of iron has the reaction 4 Fe + 3 O2 equals 2 Fe2O3. So every 2 moles of iron produces 1 moles of iron oxide. 16.7 grams is .299 moles of iron. This means there are 0.149 moles of iron oxide or 23.88 grams.