a is selected by 63 out of 287 - a rate of 63/287.
b is selected at a rate of 23/301.
Selection rate for a/selection rate for b = (63/287)/(23/301) = 0.2195/0.0764 = 2.8727
Ie a is likely to be selected 2.8727 times as often as b, or a is 1.8727 times more likely to be selected.
Comparision between binomial plus normal plus hypergeometric distribution?
The binomial distribution is a discrete probability distribution which describes the number of successes in a sequence of draws from a finite population, with replacement. The hypergeometric distribution is similar except that it deals with draws without replacement. For sufficiently large populations the Normal distribution is a good approximation for both.
About 2/3 of the time.
If you toss a penny how do you think the coin will land heads or tails explain?
there is even chance of having heads or tails since there is only 1 head and 1 tail on a penny.
A definition and an example of multiple representation?
it's basically higher order thinking ex) 3+4-2*4dived by 8= e
What is the probability of flipping NO heads when you flip 3 identical coins?
The chance of not flipping a head in each instance is 1/2. You need that to happen three times.
1/2 x 1/2 x 1/2 = 1/8
So there is a 1 in 8 chance of getting no heads from 3 coin flips.
Lucy and her friends each have seven cards, as one third of 21 is 7.
How many card that is not a diamond face card?
There are 52 cards in a deck. 52cards/4 suits = 13. 13x3=39. There are 39 cards in a deck that are not diamond.
When apply geomatric distribution?
When you want to find the probability of something happening for the first time while repeating an experiment, you use the geometric distribution. For example, you are throwing a six-faced die and you are expecting the number '6' to be thrown for the first time.
What is the probability of rolling a sum which is a multiple of five?
There are 36 permutations of rolling two standard dice. Of them, four (1+4, 2+3, 3+2, and 4+1) sum to five, and three (6+4, 5+5, and 4+6) sum to ten. The probability, then of rolling a multiple of five is 7 in 36, or about 0.1944.
What is probability that she will pick a tennis of 4 that she has?
if they are all tennis balls, then 100% percent
How many ways are there to arrange the letters in the word ADDRESS if the two Ds must be together?
The permutations of the letters ADDRESS if the two D's must be together is the same as the permutations of the letters ADRESS, which is 6 factorial, or 720, divided by 2, to compensate for the two S's, which means that the number of distinct permutations of the letters ADDRESS, where the two DD's must be together is 360.
You see, if you are drawing in a piece of paper, then it is two dimensional.
Give an example of how to find the standard deviation?
Look at the Wikipedia article on "Standard deviation" - it includes an example right at the beginning.
What are odds of all six numbers on six-sided dice appearing if you roll seven dice?
The probability is 15120/279936 (35/648 in lowest terms), or about .054 (about 1 time in every 18.5 tries). Verified by simulation.
Usually people asking for odds actually mean probability, but in case it really is what you want, the odds would be 35:613 (ratio of win:lose).
How to get it: Think about rolling the dice one at a time, and start with the (simpler) case where it's the first six dice that have all six numbers. The number of ways of arranging the six numbers in the first six positions is 6!. Then the seventh die can be anything, so there are 6! * 6 ways that the first 6 dice have all 6 numbers and the 7th can be anything.
Call the 7th die (the one that can be anything) the "odd die". The odd die doesn't actually have to be last - it could be rolled anywhere in the order, so it could be the 1st die, the 2nd, etc. This means we have to multiply our previous number by 7 to account for every possible position of the odd die. (we're up to 6! * 6 * 7 ways to succeed)
Finally, if you think about it, we've counted every ordering twice, since the odd die must match one of the other dice. For example: one way to succeed that the above method counts is 1 2 3 4 5 6 1 (with die #7 being the odd die). This exact same roll is also counted when we consider die #1 to be the odd die, and it matches the last die. Therefore we've counted the same roll for two different positions of the odd die. Since this happens no matter what or where the odd die is, we will have counted each successful roll exactly twice. So divide our last count by 2 to get the final answer of 15120 ways to succeed.
There are 6 ^ 7 = 279936 possible outcomes when rolling 7 dice, so the probability is 15120/279936.
What is the value of a minute?
well, just a single minute keeps alot value for e.g within a minute we breathe more than 40 times,just in a minute 1000s of galons of water are filled,just in a single minute life-taking or life-giving decisions are taken!
aaahh............!!!!!!!!!!
JUST IN ASINGLE MINUTE......!!!! A minute is priceless if it's the last one you've got. Otherwise, it's useless judging from how most people use them.