A student must answers 8 out of 10 questionshow many choices does the student have?
This is a combinations question. The answer is C(10,8), the number of combinations of 10 things taken 8 at a time, which also equals the number of combinations of 10 things taken 2 at a time. You can imagine why these are the same: choosing 8 questions to answer out of ten is the same thing as not choosing 2 questions to answer out of ten. C(10,2) = (10*9)/(2*1) = 45. There are 45 different choices the student can make of which eight questions to answer.
What is probability of getting 6 in a role of dice?
1/6, because there are six sides, so it would have to be 1 chance out of those six. :)
1/4? ...
What is the probability that you don't roll a sum of 3 when you roll two fair dice?
I think of it this way. Take it as two unique 6-sided dice, then you have 36 possible outcomes (6 times 6). Two of these outcomes will add to equal 3 (2 & 1, and 1 & 2), so there are 34 [36-2] outcomes which don't sum to 3. The probability is 34/36 or about 94.44 percent chance.
If you're asking what the probability you don't roll AT LEAST three is, the only roll on two normal dice less than three is two, and there's only one way to roll it: 1,1. So the probability of not getting AT LEAST three on two fair dice is 1/36.
What is the chance of you selecting a king from a deck of playing cards?
4 possible kings out of 52 cards.
1/13
An ace of spades is one of the 52 playing cards in a standard set, with a single pip and the nominal value of 1, with the spades suit.
What is the theoretical probability of rolling a 10 after rolling the dice 50 times?
I'll answer your question literally before guessing at what you really meant.
The probability of rolling a 10 is not influenced by what was done before, assuming perfect dice, of course. So the fact they were rolled 50 times before makes no difference, the probability remains 1 in 12.
But maybe you meant, "What is the theoretical possibility of rolling a 10 at least once in 50 throws?"
To figure that out, you work out the opposite and then take 1 minus that.
You ask yourself, "What is the probability of NOT rolling 10 in 50 throws?"
Now that's easy. The odds for any one throw is 33/36 (there are 3 ways to throw 10: 4&6, 5&5, 6&4). So the odds of no 10 in 2 throws is (33/36)x(33/36) and for 50 throws, it is (33/36) to the 50th power.
That is an extremely small number, so the opposite (chance of at least one roll or 10) is almost a sure thing (1 - (33/36)50).
It is an event that is certain.
It is an event that is certain.
It is an event that is certain.
It is an event that is certain.
1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160, -1, -2, -4, -5, -8, -10, -16
THE RANDOM METHOD (: :P THE RANDOM METHOD (: :P THE RANDOM METHOD (: :P
What are the odds of eight matching dice out of ten die in one roll?
The odds of one die being any number is 1 in 1. The odds of any of the next seven dice being the same as the first die is 1 in 6. The odds of the last two being different than the first die is 5 in 6.
The dice are unrelated to each other, and it does not matter in what order they are thrown, so the odds of eight matching dice out of ten dice is (1 in 1)1 (1 in 6)7 (5 in 6)2, or 25 in 10,077,696.
If a spinner having 2 colors red and blue is spun twice what is the possible outcome?
it will land on red once and it will land on blue once aswell