Probability

this isn giong to be my answerP(tails and 5) = 1

P(tails or 1) = 2

z score

It depends on the country and societal norms of the researcher as well as the seriousness of the offense. Generally, dishonesty in the laboratory is not a crime and so is not punished in this way. However, if for instance the research was done for medical purposes (studying the effects of a medicine for instance) and the bad research results in deaths, the consequences can be quite serious (in the US, this would still not be taken up by a criminal court of law, but rather a civil lawsuit). More often though, such dishonesty just results in the researcher getting a very poor reputation, and perhaps the loss of his/her job and loss of sources of funding for research.

Because each can occur in only one case. If you roll two, 6-sided dice the only way to get a sum of 2 is when they are BOTH 1's. The only way to get a sum of 12 is when they are both 6's. Thus these are the two least likely (most extreme) sums. For example there are two ways to get a sum of 3 (a 1 on one and a 2 on the other OR the reverse) or 11 (a 5 on one and a 6 on the other OR the reverse). There are even more ways to get 4 (1-3,3-1,2-2)...

The result is not a multiple of two if the sum is odd

That is, if one die is odd and the other is even

That is, die 1 is odd and die 2 even OR die 1 is even and die 2 is odd.

There are 18 such combinations

So 18 out of a total of 36 = 18/36 = 1/2

So the probability is 0.5 or 50%

"Gambling" is an eight letter word.

If the illness is infectious then you cannot use the binomial distribution because the incidences of illness are no longer independent events, so that the assumptions required for the binomial distribution are not satisfied.

Suppose the illness is not infectious and the "normal" rate of illnesses is p. Then in a group of size n, the number of units suffering has a B(n, p) distribution. You can then determine a critical region at an appropriate level of significance and test the number of victims against that.

50*7 = 350

108295 x 0.772 = 83603.74

There are four 2s in a standard deck of playing cards.

ther are 4 8's.....4/54=1/13

There are 26 of them.

1 is special.

2, 3 and 5 are primes.

4 and 6 are composite numbers.

So, the prob. is 2 out of 6 - which is 2/6 = 0,33333 = 33,3 %

what are the kinds of probability?

A group of quantities connected by operators gives the same result whatever the order of the quantities involved.

1 + 2 = 2 + 1

50/50 really if you think about it depends on the driver.

assuming that it is a regular die with numbers 1-6 on them the probability is 1

The browser available here is not suited for the purpose. You will need to refer to a statistical site or even a book!

I've included a couple of links. Statistical theory can never tell you how many samples you must take, all it can tell you the expected error that your sample should have given the variability of the data.

Worked in reverse, you provide an expected error and the variability of the data, and statistical theory can tell you the corresponding sample size.

The calculation methodology is given on the related links.

Because other than in a degenerate case, the maximum of a set of observations is not at its centre! And the theorem concerns the distribution of estimates of the central value - as the name might suggest!

Depends on the architectural design. There could be 1 to n stories (levels) in the house. The cards could be laid on the short or long side. The angle at which the cards are leaned toward each other could differ.

(I think he meant using the original Pyramid type stacking)

16

2/12 or 1/6