What has the author F X Linsenmann written?
F. X. Linsenmann has written:
'Worte der Erinnerung an Moriz von Aberle, Doctor und Professor der Theologie'
The number 31 is not the square of a whole number. It is the square of 5.5678.
How does connecting the points on a graph affect your data analysis?
They make points in space related to each other. Now they are connected in the problem, instead of just points on the graph.
sorry but are gone mad
How do you multiply -2 x 3over-8 x -5over7 and put it in simplest form?
-2 * 3/(-8) * (-5)/7
There are three negatives being multiplied so the final sign is negative.
- (2*3*5)/(8*7) = -15/28
-2 * 3/(-8) * (-5)/7
There are three negatives being multiplied so the final sign is negative.
- (2*3*5)/(8*7) = -15/28
-2 * 3/(-8) * (-5)/7
There are three negatives being multiplied so the final sign is negative.
- (2*3*5)/(8*7) = -15/28
-2 * 3/(-8) * (-5)/7
There are three negatives being multiplied so the final sign is negative.
- (2*3*5)/(8*7) = -15/28
How do you solve 11-9m equals 2?
This may get complicated. Try and stay with us if you possibly can:
11 - 9m = 2
Subtract 11 from each side:
- 9m = -9
Divide each side by -9:
m = 1
What does x equal in this equation- 4-2y plus 2?
Since there is no x in the equation, it can equal anything at all!
X2/X
= X
=======
I do not think you can divide one variable type by another.
The log of a quotient is the log of the numerator minus the log of the denominator?
True.
For example:
4 X 104/2 X 108 = 2 X 10-4
What is the answer for 7 plus 3 x -3?
When solving these types of problems, follow BEDMAS.
B-Brackets. You always answer the equation in the brackets first.
E-Exponents. For instance, 3 to the power of 3 isn't the same as 3x3 because you're multiplying 3x3x3=27.
D-Division
M-Multiplcation. Division and multiplication go together. For example, 8x2 divided by 4. Even when you divvide 2 by 4 first, then multiply 8 by 2, it's the same product as doing it the other way around, but you must always answer from left to right when it comes to division and multiplication; and addtion and subtraction, but with brackets as an acception.
A-Addition
S-Subtraction *These go together!
Now, using BEDMAS, you can now answer the operation.
7+3x3
=7+9 (because 3x3=9)
=16
Which point lies on 2x plus 5y equals 10?
First, in this form. Y =mX + c
2X + 5Y = 10
5Y = - 2X + 10
Y = (-2/5)X + 2
Y = 2
----------0 out equation
(- 2/5)X + 2 = 0
(- 2/5)X = - 2
X = 5
---------
(0, 2) and (5, 0)
------------------------------ points on the line
What is the answer to 100 - 8 x 7 plus 23?
Bodmas ( brackets, powers, division, multiplication, addition then subtraction).
100 - 8 x 7 +23.
100 - 56 + 23.
100 - 56 = 44 + 23 = 67.
What is the 170.05 the sit gives a 5 percent percent discount?
170.05 is 5% less than 179.00 .
5% less than 170.05 is 161.55 .
By the remainder theorem, if the remainder, on division by (x - 3) is 17
then substituting x - 3 = 0 or, equivalently, x = 3 will give a value of 17 in the original expression.
Thus
33 - 3*32 + 3n + 5 = 17
So that 3n + 5 = 17
that is 3n = 12 or n = 4
_______________________
I do not see how this question can be answered when there are two unknown variables.
It is suggested above the answer is that n equals 4.
Let me substitute a random value for x.
x = 2
Would give:
(8 - 12 + 8 + 5) / (2 - 3)
= 9 / -1 = -9. There is no remainder. The remainder can not simultaneously be 0 and 17. There is an error here. (See below for why).
This question can not be answered when there are 2 unknowns.
Additional Information:-
The first answer is correct and the second answer given by another contributor is incorrect because by using the remainder theorem:-
f(x) = x3-3x2+nx+5 remainder 17
f(x) becomes f(3) because the divisor is x-3 and 3-3 = 0
f(3) = 33-3(3)2+3n+5 = 17
f(3) = 3n+5 = 17
f(3) = 3n = 17-5
f(3) = 3n = 12
f(3) = n = 4
So the value of n in the expression is 4 which makes the original answer correct.
What is system dependence graph?
A program's system dependence graph (SDG) is a collection of procedure dependence graphs (PDGs): one for each procedure.