How do you solve complex fraction?
this is a very good question. lets solve (2+3i)/(4-2i).
we want to make 4-2i real by multiplying it by the conjugate, or 4+2i
(4-2i)(4+2i)=16-8i+8i+4=20, now we have
(2+3i)/20 0r 1/10 + 3i/20
notice that -2i times 2i = -4i^2 =-4 times -1 = 4
What is the domain of the variable x if it's an imaginary number?
In (x+iy), x=any value in the real number line.
What are some unique properties of imaginary numbers?
1. i1 = i, i2= -1, i3= -i, i4= 1, i5= i, i6= -1 and so on.
2. Euler's constant e, when raised to the power of a complex number, gives a point in the complex plane according to Euler's Identity, e^(iθ
) = cos(θ
) + i*sin(θ
).
Whenθ
is replacedby pi, we get:
e^(iπ)
= cos(π
) + i*sin(π
)
= -1 + 0
= -1
In other words, e^(iπ)
+ 1 = 0.
3. Many intriguing fractals have been discovered in the complex plane, the most famous of which is the Mandelbrot Set. This is formed by an iterative process of a point in the plane. It produces a beautiful image, nicknamed by many as the "Thumbprint of God". (Google Images is your friend here - check it out.)
4. De Moivre's Theorem holds true in the realm of the imaginary, stating that
(r cisθ
)n= rncis nθ
.
This is a fascinating theorm in itself, but it also has hidden implications.
For example, if r = 1 (the point was 1 unit away from the origin), and you were to plot this point with a small angle above the positive real axis, then raising this number to an increasing power would result in that point making a full revolution about the origin and coming right back to where it started.
This is because rnstays the same (1^(anything) = 1), but the angle is slowly increasing as the power does. Therefore, as the angle increases, a circle is plotted around the origin with radius 1.
There are many other fascinations around complex numbers, but this covers the basics.
Well first you type in the numbers you need then you type in the symbol you need.
What is X when raised to the 3-5i power and the answer is 23-14i?
X = 1.31356+0.612045*i
Steps to solve, take the natural log of both sides:
ln(X^(3-5i)) = ln(23-14i).
(3-5i)*ln(X) = ln(23-14i). Convert 23-14i to exponential form: A*e^(iΘ) {A = 26.926 and Θ = -0.54679 radians}
(3-5i)*ln(X) = ln(A*e^(iΘ))= ln(A) + iΘ = ln(26.926) - 0.54679i.
divide by (3-5i): ln(X) = (ln(A) + iΘ) / (3-5i) = (3.2931 - 0.54679i)/(3-5i)
So we have ln(X) = 0.370978 + 0.436033i, then:
e^(ln(X)) = e^(0.370978 + 0.436033i) --> X = 1.31356+0.612045*i
What is the advantage of product differentiation?
A company that excels at product differentiation can normally demand a higher price for a product because of its perceived higher quality.
What is the answer to a number set of 12 numbers maximum 8mode 6range 6 median 5?
Since the maximum is 8 and the range is 6, it means the minimum must be 2.
So let's write, 2 _ _ _ _ _ | _ _ _ _ _ 8
Since there are 12 data (even) and the median is 5, it means the possible data giving us the median are 4 and 6, or 5 and 5.
By knowing the mode is 6, you can fill out the places with numbers that can fit on. for example,
2 2 3 3 4 4 6 6 6 7 7 8, or 2 2 2 3 3 4 6 6 6 6 7 8, or 2 3 4 4 4 5 5 6 6 6 6 8, etc.
What do you call a set of numbers with an exact number of points?
This is called a discrete set (all points isolated) or a finite set.
Finite sets are always discrete.
What is the complex equation for 6 less than the quotient of h divided by 2 is 10?
Do you mean h/2 -6 = 10 if so then the value of h is 32
How did complex number calculator influence modern computing?
Calculators, probably in the 1980's (I know for a fact the HP 48 calculator circa 1992 handled complex and imaginary numbers) helped people perform calculations with complex numbers, without having to figure conjugates, angles, etc. on paper.
Complex number computing was long before that.
I know that FORTRAN (developed by IBM and released in 1957) could handle complex number calculations. FORTRAN was designed specifically for scientific and engineering calculations. Check out the Wikipedia article.