Electrical Engineering

10 Ohms.

A dielectric is an insulating material that does not conduct electricity and is transparent to an electromagnetic field. Dielectric materials are used to separate conducting surfaces such as the plates inside a capacitor, wires inside transformers, electric cable conductors, and elsewhere in the electric industry where electrical separation of charged elements is necessary. The dielectric constant is a ratio of the capacitance of a capacitor in which a particular insulating material is the dielectric, to the capacitance of the capacitor in which a vacuum is the dielectric.

Its just a matter of standard. In my area, for instance, we use 13.2 KV for distribution lines, and 69 KV / 138 KV for transmission lines.

Increasing resistance decreases current.

An ammeter measures amperage not voltage.

If a motor 3 phase or single phase goes above the full load amps that is on the nameplate of the motor then it is in overload condition. This is usually caused by trying to drive machinery with less horsepower that the manufacturer recommends To protect the motor from this condition overload heaters are put in series with the supply voltage and the motor leads. If the current from the motor draws more that the motor's nameplate FLA then the overload heater opens the supply voltage through use of a motor contactor. The contactor can not be closed again until the motor overload heaters cool down and by the same token the motor gets a chance to cool down. This condition is rectified by either using a bigger HP rated motor or lowering the load on the machinery that the motor is driving.

A fuse might be a bit cheaper and the form factor may smaller if size is an issue. If the fuse blows on a regular basis it will of course end up costing more and will be more inconvenient to replace.

One uses single phase AC current (120/240), the other uses 3 phase AC current (most households will not have 3 phase in their home) One uses a 3 phase motor the other a single phase motor. 3 phase is usually used in industrial applications while single phase is used in home or small business apps.

You can think of it as a motor that is very strong. If you were to try and hold the wheel of a 1000cc motorbike you would not be able to stop it from moving because it has tremendous torque in lower gears.

High torque means greater acceleration, which means you will need better tires to prevent wheel spins.

Alternating Current is measured in Amperes.

Both AC and DC are current methods in which electrons move along a wire

14

240 volts - the turns ratio of this transformer is 2:1, thus the primary voltage will be two times the secondary voltage.

No, we don't find the output force of a system is greater than its input. We've never seen this. There are losses associated with any system, whether they be mechanical, thermal or other. That prevents a situation where we can get more energy out of a system than we put in.

We don't know all there is to know about physics, but we know a lot. If we knew how to get more energy out of a system than we put into it, we'd have applied that to generate electrical power. Consider how we provide electricity ot the power grid now and think it through to confirm the idea that we don't know of a way to get more energy out of a system than we put in. Perpentual motion isn't something we've realized, either.

Your question in ambiguous. Are you asking what equipment you need to provewhether or not Ohm's Law applies to a particular load? If so, then you need a variable voltage supply, a voltmeter, and an ammeter. As you gradually increase the voltage across the load, you will need to record the voltage and current values. If the resulting graph is a straight line, then the load is 'ohmic' (or 'linear') and obeys Ohm's Law. If the resulting graph is a curved line, then the load is 'non-ohmic' (or 'non-linear') and does not obey Ohm's Law.

we proceed via the FT of the signum function sgn(t) which is defined as:

sgn(t) = 1 for t>0 n -1 for t<0

FT of sgn(t) = 2/jw where w is omega n j is iota(complex)

we actually write unit step function in terms of signum fucntion : n the formula to convert unit step in to signum function is

u(t) = 1/2 ( 1 + sgn(t) )

As we know the FT of sgn(t) we can easily compute FT of u(t).

Hope i answer the question

Current (amps)=Watts/Volts =2000/120 =16.75 =16.75 amps

A three-phase meter can be used for single phase while the reverse is not the case.

Because ammeters have low resistance. If you connected them in parallel, all the current would flow through the ammeter instead of the circuit you were trying to test, possibly frying the meter but certainly invalidating the measurement.

At STP(Standard Temperature and pressure), the temperature is zero degrees Celsius(273 Kelvin) and the pressure is 1 atmosphere. At RTP(Room temperature and pressure), the temperature is 25 degrees Celsius(298 Kelvin) and the pressure is 1 atmosphere.

For a very basic explanation, a manometer measures the pressure differential between a closed pressure applied at one end and an open pressure at the other.

For example. If you have a typical u-bend manometer and you apply an air pressure at one end, the liquid will raise correspondingly, as the pressure on the closed side increases more and more above the ambient air pressure.

The amount it rises depends on the density of the liquid used and the diameter of the tubing.

So basically a manometer uses the height of a liquid to translate the amount above ambient air pressure, which is considered zero, of your pressure source.

A transformer is an electrical machine whose purpose is to either 'step up' or 'step down' a voltage. For example, the voltage generated by an alternator in a power station is far too low for transmission, so a 'step up' transformer is used to increase that voltage to transmission levels. Transmission voltages are then gradually reduced, using 'step down' transformers at load centres (e.g. towns) where the electricity is to be used.

First of all, a megawatt is not a unit of energy. It is a unit of power, or the rate at which energy is used. 1 watt corresponds to 1 joule per second. For example, a sixty watt lightbulb uses 60 joules of energy per second. So a megawatt is one million watts, or one million joules of energy per second. Electrical energy is often measured in kilowatt-hours by the electric company (So that they know how much to charge you). This is equivalent to the amount of energy that a kilowatt power source could supply in one hour. The amount of energy in joules that a kilowatt hour is goes as follows: 1 kilowatt = 1000 watts, so 1000 joules per second. Multiply this by the number of seconds in an hour, and you have 3600000J.

Charge the capacitor with a voltage source through a resistor. Keep track of how long it takes the capacitor to charge to the voltage level. The value of the capacitor is c=time/5R where R is the value of the resistor and time is the charging time.