Electrical Engineering

Yes, you can substitute a 250 volt fuse in place of a 125 volt fuse. You just can't go the other way around.

As far as 1.5 amperes in place of 3 amperes, well, you've got a problem there because the fuse will blow at about 1.5 amperes instead of 3 amperes, so the intended load will not be met.

All of this, of course, assumes that the physical size of the fuse is the same.

Bottom line is never substitute fuses.

The furies in this game are completely invincible. They cannot be killed in any way. The idea is to avoid venturing in water for too long to make game more strategic and fast paced. If you're playing it on PC try to find and install mod which will make furies killable although I couldn't guarantee it exists

a wave winding in which the number of parallel circuits is a multiple of two, other than four, whatever the number of poles

A: Follow me on this the lm317 is a 1.25v regulator period. So to make it look like a 11.25 volts is simple assume the the regulator load is 125 ohms so the current through will be 1.25 volts divided by the 125 ohms or 10 ma. now install a resistor from the adj terminal to ground to IR drop 10v which will be added to the 1.25v so 10v divided by 10 ma =1000 ohms from adj to ground will offset the voltage by 10 plus the 1.25 volt give us 11.25 output from output to ground. since we offset the output voltage by 10 volts the adj pin only needs very little current we could have use 1250 ohms and 10k to achieve the same thing. There is a formula to calculate the output voltages but if you understand this you will have no problems. And by the way this scheme can be used for a 5 v,12v any of the three pins regulators. By changing the 1k you will change the output volts since the 1.25 volts is fixed and the 125 ohms if fixed. Furthermore to make it behave like a current source up to an amp or so all you need is a resistor in series with the load and take the output at the adj terminal and good luck.

when we replace the resistor with a capacitor ,the current will flow until the capacitor charge when capacitor will fully charged there is no current through the circuit because now capacitor will act like an open circuit.

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A relay is basically a controllable switch that connects a supply voltage to a load. If the relay is switch such that the load is not connected, that could be considered an open load. If it is switched the other way the load will be connected to its supply voltage. A defect in a relay would be something that caused it not to function correctly. It could be in the switch portion of the supply portion of the relay. Hence you are referring to different things and a defect may or may not cause the load to be open.

No you can not it's 31 amps

A: Three way must have a resistance and voltage source and current source to a very close tolerance,

'Electricals' isn't a scientific or engineering term, so it can mean whatever you want it to mean, depending on its context. Some electrical appliance stores, for example, advertise that "We specialise in electricals", meaning that they sell refrigerators and washing machines!

Yes, but you should add a bleed resistor in parallel to a motor run cap if you want to use it for a hid ballast to drain the cap when its not in use, this is to avoid dangerous voltages remaining in the cap, and remove the potential for electrocution

connect a register in series with line and take the voltage at the register terminal if circuit is close.

There are two. Positive + and Negative -

Positive is carried by the proton and negative is carried by the electron.

What is usually talked about when people talk about charge is electrical potential.

At zero potential there are equal number of electrons and protons. But in the real world that seldom happens so electrical potential is correct the potential difference between the state of two objects. In other words which one has the most or least electrons compared to its number of protons. Since this is hard to count we are lucky that the excess one of the other creates an electrical field and we can measure the strength of the field as a measure of the charge. The most common device to do this is a voltmeter which measures the electrical potential difference between to conductors such as the ends of a battery. There are other devices to measure the magnitude of static electrical fields.

Mix it with a local oscillator whose frequency is (the IF frequency) away

from the frequency of the FM signal you're interested in.

yes

Unwanted or high resistance in a automotive circuit is usually caused by corrosion around terminal points. Start at the battery terminal connections and work your way through the circuit cleaning any terminal corrosion that you see. Take the termination apart and clean the faces that touch each other. If possible tape the joint to keep air from the connection as it is this oxidation that is the main culprit.

The two outside contacts (of four contacts) are connected to the power supply in the computer.

28 + 56 = 84 ohms

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The input voltage, an AC Sine Wave will have a Peak-to-Peak value equal to 2X its Peak value. Once rectified, all the Peaks will be either above or below the Zero reference line. They'll look like a series of identical bumps.

The net value of the unrectified voltage will be Zero. The positive and negative waveforms canceling each other out. The rectified waveform will be all positive or negative and its net value will be non-zero.

Its AVERAGE value will be .636 times its Peak value. Its Root Mean Square (RMS) value will be .707 times its Peak value. Its Peak-to-Peak value will equal 1X the Peak value.

Zener Diodes like all other diodes use a semiconductor P-N junction. The focus of this topic is actually more on the semiconductor characteristics than the diode it self. Semiconductors are not conductors and do not exhibit the same behavior than conductors. In this section free electron band and conductive band are used synonymously and Fermi level is a quantum mechanical term I can roughly define in semiconductor physics for a basic understanding as the kinetic energy of the electron in the highest quantum level.

Semiconductors do not have electrons in the conduction band. All electrons are bound in covalent bonds and their valance bands are nearly filled under normal condition. It is required for an external energy to increase the Fermi level of the electrons in the valance energy band to jump the energy gap (forbidden band) into the conduction band. Then the semiconductor becomes conductive. Thermal energy is one type of energy that can raise the Fermi level of the fermions (particularly electrons in this case) in the valance electron band to jump the energy gap into the conduction band. This will increase the probability for an electron to find it self in the conduction band resulting in the semiconductor to become more conductive. In this case we will see that the contribution that thermal energy makes to increase conductivity by raising the Fermi level is much more than the contribution thermal energy makes to increase resistance, by making the atoms vibrate more, increasing collusions between electrons. This cause the semiconductor to form NTC (negative temperature coefficients), The higher the temperature the better it conducts within normal boundaries.

With conductors, they already have electrons in conductive bands and by adding energy to it will not make that much difference in the amount of free electrons (conductivity). This cause a very small contribution to increasing conductivity. But the contribution to increase resistances are far greater due to the vibration of the atom causing more collisions between electrons. This give conductors a PTC (positive temperature coefficient) in normal conditions and cause the electrical resistance to increase when temperature increases.

One can also take note that not only silicon Si and germanium Ge are semiconductors, but carbon only appear to be a conductor because it conducts electricity and often misunderstood on "school science" level. It is actually a semiconductor and also have NTC (negative temperature coefficients).

Graphite can conduct electricity due to the vast electron delocalization within the carbon layers, a phenomenon called aromaticity. These valence electrons are free to move, so are able to conduct electricity. However, the electricity is only conducted within the plane of the layers.

if the input is changed then the output is also changed.

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Branch-current analysis isn't as foolproof or effective as mesh analysis, or node analysis. Although it is a very good method for one who is studying circuit analysis for the first time. Mainly because it allows you to get familiar with both of Kirchhoff's laws, and if understood, will broaden your understanding of the other methods. It will also make you appreciate them all that more... ;).

Volts is not a measure of energy so there is no way to have 18volts of energy. Energy is measured in Joules, or sometimes calories.

Watts is a measure of energy transferred per second. In electrical terms, 1 Watt is equal to 1 Volt at a current of 1 Amp. In one second, 1 Watt will transfer 1 Joule of energy.

There could be a number of reasons. A 7805 has three pins: Voltage in, voltage out and an earth.

If the earth is not tied to the earth reference (ground) of the circuit, the output will be held close to the input voltage.

If there are no suppression capacitors on the inputs and outputs, high frequency oscillation can be present and at a level where some meters will read it as a DC shift.

The IC may be damaged. It has a maximum input voltage of around 35V (dependent on the specific IC). Exceeding the input voltage doesn't do the IC any good at all.

The other possibility is that the output side of the IC is being fed with a voltage from another part of the circuit.

Keep taking the meter readings with the IC in circuit and out of circuit and one of these errors is likely to show up.