i dont know maybe your lightbulb is messed up. There could be many possibilities depending on the situation. If a high wattage unit comes on (like an air conditioner), there could be a drain on the system that causes a light to dim. Sometimes during a storm, there could be a problem at the power substation including a power surge or break in the system, that could cause lights dimming. If too many strands of lights in a series are connected, you run the risk of overloading that circuit, which could cause dimmed and blown lights, and potentially dangerous situations.
Consult a Master Electrician for more information.
When an electric bell is operated, a current pass through an electro-magnet intermittently. The plunger moves back and forth due to intermittent magnetic operation. The moving plunger or lever connected to it hits a metallic body intermittently to ring the bell. The movement of plunger itself cuts off and cuts in the electric circuit intermittently.
This question is nonsensical, there is no answer.
230V AC describes a 230 volt potential (in form of alternating current), but does not imply a minimum, maximum or actual current (ampere).
In Western Europe, 230VAC or 240VAC domestic circuitry is typically fused with 13A, 16A or 20A, but other values are possible and common.
Well, first off most cents are zinc now, but in any case using a coin to replace a fuse is a very bad idea. A fuse is designed to be the weak link in an electrical system. It's intended to fail before any other part of the system does, so that expensive things like stoves, TVs, and inside-the-wall wiring don't fail in the event of a serious electrical problem. And even more important, a failure of one of those items could cause a fire!
Bottom line, keep some spare fuses on hand, or if possible have a licensed electrician replace the fuses with circuit breakers. They're special switches that open up during a over current fault or overload so they protect the system just like a fuse, but they can simply be reset after the cause of the overload has been fixed.
Thermocouple is a heat sensing device.
It is made up of 2 dissimilar metals twisted/joined at one end called a junction and that is made Hot and the other end or tell end is cold (may be at 0 degree C). then a voltage is developed accross the two dissimilar metal, this principle is called SEEBECK EFFECT.
The voltage developed is directly propersional to the difference in temperature.
There might be 3 reasons for this:
1. The fuse in the power plug has gone.
2. There might be a damaged part of the wire.
3. The PSU might have either died or not connected properly.
"Locked Rotor Current" also called LRA which stands for Locked Rotor Amps, is commonly found on electric motor nameplates. Locked Rotor essentially means the motor is not turning. The current or amps in this case have to do with the amount of electrical energy required to start the motor. At the instant the motor is switched on, it is not turning, and draws the maximum current. As the motor starts to turn, the current goes down. This required energy is much greater than the Full Load Amps or Running Amps, which is the current drawn when the motor is running at normal speed under full load. The current required to start the motor will depend on the type of motor as well as the specified design voltage required for the motor, typically the higher the voltage, the lower the required amperage or current.
The term also applies to equipment such as Air Conditioners which have an enclosed motor inside the compressor, as well as the condenser fan(s) etc.
Depending on the type of motor, LR current can be anywhere from 3 to 8 times the normal running current, also called RLA, or running load amps.
1. Pin point the problem - what is not happening as expected.
2. Read the error messages, error codes if any from the equipment.
3. Refer the manual for troubleshooting points follow the steps provided.
4. Talk to the expert and explain the problem and inform the observed behavior of the equipment.
What causes wires to burn in terminal strips is the lack of tightness between the set screw and the conductor. A loose junction will start to arc. Minor at first but as the oxidisation from the heating and cooling continues the resistance of the joint becomes higher.
As the resistance becomes higher the more amperage is needed to flow through the joint to operate the load. The heating of the conductor will get high enough to melt the insulation from the conductor. Once the insulation is gone this becomes conducive for a short circuit to occur.
If the wire gets hot enough and the circuits breaker does not trip, the wire can completely burn off from the terminal strip and the circuit will open.
Usually the type of fuse is encoded into the fuse number. For example a English Electric fuse C20J, the C represents that the fuse is a cartridge type, the 20 is the amperage of the fuse and the J represents the speed of the fuse. Also the J states that the fuse is a type J fuse.
Zero watts can be installed in 1000 micro farads. Watts are the product of amperage times volts. Micro farads is a value used in talking about capacitance.
The amperage drawn from batteries is governed by the connected load. The voltage of the batteries can be one of two voltages. in parallel the 8 batteries will give you a voltage of 6 volts. In series the 8 batteries will give you a voltage of 48 volts. The amp/hour capacity of the batteries will give you the amount of current the device can draw over a specific length of time. Equation to fine amperage is I = W/E, Amps = Watts/Volts. Watts = Amps x Volts.
This is a common phenamenon when the atmosphere air is dry (generally during winter). When you are sitting inside the car for some time, you generate a static charge and it gets released when you touch metalic handle of the car
You need to first know the wattage of the motor and locked rotor current can be tested at a lab only
I can see that the best answer has already been given (the units aren't even remotely close). But suppose that what the asker meant was 125 kVA? In that case, it can be answered.
VA (or Volt-Amperes) is what's used to represent current consumption when the circuit runs on any form of alternating current (AC). Watts (W) don't apply, because of the inherent properties of a changing waveform. To properly calculate the actual put-into-use (or effective) power, one would have to take the entire circuit into account.
But, to answer the speculated question, I would say - anywhere between 125 kW and 0 kW, depending if the load is purely resistive, or purely capacitive in nature, respectively.
(this answer provided for the benefit of Google click-throughs, mostly)
An Ohmmeter or the ohms function on a typical multimeter would be used to bench test a motor for a short or an open winding. First, be absolutely certain that the motor under test is disconnected from any mains. Using a low ohms scale, x1 or x10, one would expect to see some resistance across the motor. The resistance can be quite low depending on the size of the motor, but should not be zero. If it is a motor that has brushes and a commutator, rotate the shaft, with the meter connected, through a full revolution. This rotation could help identify a single defective winding in the rotor. To check the stator, remove one of the brushes so that the measurement current only passes through those windings. Of course, it would help if you have a known good motor of the same kind so that you can compare the readings.
First thing voltage does not flow current does. Voltage is the potential or pressure needed to make the current flow.
Current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. To make the current flow you have to adjust the resistance of the circuit and that would be the water in this case. Salt added to water will make the water conductive so the resistance can be adjusted thereby making the current rise or fall depending on the water solution's resistive properties. The equation that you should consider using is Amps = Volts/Resistance.
Draw two parallel vertical lines on a piece of paper. Visualize these as a left side and a right side of an upright ladder. The left side will be called the "hot" wire and the right side will be the neutral wire. The cross pieces in this diagram will be the rungs of the ladder. Draw a line from the left hand side of the ladder to the right hand side of the ladder. Insert into this rung one of the two light bulbs. Below this rung copy the above rung with the second light bulb. Into this second rung insert a switch in series with the second bulb. When the complete circuit is powered on the first bulb will light and depending on the position of the switch in the second rung, the second bulb will light if the switch is closed. If the switch in the second rung is open the bulb will not light.
This will be the drawing that your scenario suggests.
Check the circuit breaker to see if it tripped.
The main rule to be followed when using an ohmmeter is to have the circuit under test de energized from the power source.