Electronics Engineering

The M is short for Mega, which is 1 million.

The Hz is short for Hertz, the measure of frequency.

MHz is therefore short for Mega Hertz, or 1 million Hertz.

It just transmits the level of the fluid into electric signal to level indicator and this level indicator will show current level of fluid.The whole setup is used for level measurement.

A Level Transmitter is simply an instrument that provides continuous level measurement. Level transmitters can be used to determine the level of a given liquid or bulk-solid at any given time. This is different to a level switch which only alarms when the level of material (liquid or bulk-solid) reaches a predetermined level.

the resistance of liquid to following is its viscosity.

Slide Switches work on the principle of connecting disconnected parts to each other. The 'switch' connects two parts allowing the current to pass through it. Ash.

Current measures the flow of electrons through a circuit and voltage basically measure the amount of available electrons.

A current transformer (or CT) is constructed in a specific way so as to step down the current in a high power circuit for measuring or protective relaying purposes. Typically, it will have a toroidal-shaped iron core with the secondary windings wrapped around it. the primary "winding" is usually the conductor of the main power system passing directly through the hole in the center of the CT. As a result of this construction, if the secondary windings are left open, a very large flux can develop, resulting in damage to the CT and possibly even the other equipment it is attached to. As such, if the CT is not going to be used, its secondary windings need to be shorted.

Voltmeters are connected in parallel with the components whose voltage or voltage drop you want to measure. That means that the internal voltmeter's resistance will create a new branch in parallel with the component, thus increasing the current in the circuit.

If there are other components in series with the component to which the voltmeter is connected, this increment of current will increase the voltage drop across them, reducing the voltage drop across the component whose voltage is being measured. This is obviously an induced error in the measurement, which adds up to other errors built into the voltmeter (accuracy, resolution, linearity, parallax, etc.)

When measuring the output voltage of low resistance (high current) power supplies, the input impedance is usually not an issue. However, when measuring a low current power supply, the input resistance of the voltmeter will have to be at least 10 times the internal resistance of the power supply. Otherwise, the error will be too noticeable.

Therefore, the ideal voltmeter should have an infinite internal resistance. Since this is not the case, it should at least have several megohms.

Analog voltmeters usually have s sensitivity of 20 to 30 kilohm per volt (kΩ/V), which varies withe the voltmeter range setting.

Digital voltmeters, instead, have constant high (>20 megohms) input impedance, which is a combination of pure resistance and reactance, usually capacitive, regardless of the voltage range. That is why the specs of a digital voltmeter always indicate the input capacitance.

electrons

A: It is basically a glass vacuum enclosure whereby electrons are emitted from a cathode by a heating element. A grid control the flow of these electrons and finally hit the face of the tube where is rare earth materials emit photons

Rather trying to explain all the technology that goes into battery construction, go to Related Links. All your questions will be answered there. AH means Amps Hour every battery has that term stated What it means is so many amps can be supplied for so many hours. Means amps Vs time

Analog

Electrons flow from negative to positive. In an auto, it's actually flowing from your chassis to a more positive part of the circuit (less electrons).A conductor can hold a variable number of electrons. For instance, one particular conductor might be able to have 4 or 5 electrons.

If it has 4, then it will snatch one from another Atom that has 5. If it has 5, it will give up one electron to an atom that has only 4. The most positive part of the circuit has a electron deficit (a stupid way to say it, i know). This determines the direction of travel.

In a perfect conductor, electrons flow at the speed of light. Conductors that are used in the real world cause a delay in the speed of electron flow.

This answer is incorrect. Electrons always move below the speed of light. They have mass. This is a popular misconception. Electrons in a perfect conductor would move fairly quickly, but for example, when you flip on a light switch, the flow of electrons through the wire occurs at roughly a rate of 8.4 cm/hour. It's the entire flow along the tube that starts from one end, and simeultaneously pushes the other end that creates the illusion of instant action.

A capacitor joined with a sinusoidal voltage source will bring about a relocation current to move through it. For the situation that the voltage source is V0cos(ωt), the displacement current can be communicated as:

I = C \frac{dV}{dt} = - \omega {C}{V_\text{0}}\sin(\omega t)

At sin(ωt) = - 1, the capacitor has a most extreme (or top) current whereby I0 = ωCV0. The proportion of crest voltage to crest current is because of capacitive reactance (signified XC).

X_C = \frac{V_\text{0}}{I_\text{0}} = \frac{V_\text{0}}{\omega C V_\text{0}} = \frac{1}{\omega C}

XC methodologies zero as ω methodologies endlessness. In the event that XC approaches 0, the capacitor looks like a short wire that emphatically passes current at high frequencies. XC approaches boundlessness as ω methodologies zero. On the off chance that XC approaches unendingness, the capacitor looks like an open circuit that ineffectively passes low frequencies.

The current of the capacitor may be communicated as cosines to better contrast and the voltage of the source:

I = - {I_\text{0}}{\sin({\omega t}}) = {I_\text{0}}{\cos({\omega t} + {90^\circ})}

In this circumstance, the current is out of stage with the voltage by +π/2 radians or +90 degrees.

it's highest swing positive or negative. 90 and 270 degrees. the peak for a 10vAC generator would be 10vAC

In the basic configuration, a capacitor is constructed with two parallel conductor plates with a layer of insulating material in between. When the cap is hooked up to the AC power supply, the voltage (v) across the plates and the charge (q) induced on the plates follow this capacitance expression:

C = dq/dv or i = C dv/dt, where C is determined by the properties of the insulating material and the geometry of the cap (in the case of the parallel plates, the separation between the two electrodes (t).

For the parallel plates, C can be written as (dielectric constant * plate area / t). Electrically, the change in the charge induced on the plates (dq), is directly related to the change in voltage difference (dv) between the two plates, since C is a constant. Theoretically, no energy is lost by charging and discharging the cap with an AC current. When the cap absorbs electrical energy from the power supply, it stores the energy in the electric field in the insulator. When discharging, the cap gives the stored energy back to the circuit -- hence, no energy loss.

In a circuit, we use the cap to prolong/smoothen/resist any voltage change in time or to absorb a sudden energy surge (electrostatic discharge and power-line glitches, for example).

In most cases it is a dual-slope integration ADC (analog to digital converter).

This is known as a direct current or DC. The two major types of currents are AC (alternating current) and DC (direct current). In AC the charges move back and forth, but in DC the charges flow in JUST ONE DIRECTION. Due to this characteristic it will not reverse direction like AC can.

That depends on how much resistance is called for through the engineering, there is tiny resistance (mf) microfared on up huge resistance seen on electrical poles. Your circuit engineering formula dictates the needed resistance or it will just burn or not flow at all, you cannot answer the question without first asking a question..How much resistance do you need. They can be produce for virtually any tolerance.

The subwoofer is the actual speaker making the loud bass. The amplifier is what powers the subwoofer and makes it work how it does. It only uses the low frequencies from the audio source and amplifies it.

The center tapped full wave rectifier depends on two similar windings, each 180 degrees out of phase with respect to each other. You are only going to get that with a center tapped winding. Without the center tap, you need four diodes.

Yes, although the question is poorly formed. The ratio of the voltage in the primary winding to the voltage in the secondary winding is the same as the ratio of the number of turns in the primary winding to the number of turns in the secondary winding. For example, if the primary had 1200 turns with the secondary having 120 turns, and the primary voltage was 50 volts, then the secondary would be 5 volts. This is a ratio of 10:1.

A "three-phase system" is a polyphase system having three phases. The term "polyphase system" just means a system having multiple phases. If it is used by itself, "a polyphase system" doesn't mean "a three-phase system".

This is not a valid question by itself. Joules are units of energy, while Amps are units of electrical current. However, if you also know the Voltage of the electrical current, you can multiply the Current[Amps]*Voltage[Volts] to get the Power in Watts. Watts are equivalent to Joules per second. If you then know the amount of time of the current flow, you can calculate the total number of Joules by multiplying the Power[Watts]*Time[seconds] = Energy[Joules]

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The output of a common emitter stage is inverted, it is not out of phase.