Linear Algebra

Matrices can be used for circuit analysis because a circuit component can have an impedance matrix, an admittance matrix or a scattering matrix, of order equal to the number of ports the circuit has. This can also be used for antenna arrays when you have an antenna circuit connected to a feeder (transmission-line) circuit.

Matrices are also used in the numerical solution of linear equations: when you have a system of N equations it needs matrices of order N.

In field theory integral equations arise which can be solved numerically by using a piecewise-linear approximation which turns an integral equation into a set of linear equations. This is used for analysing raio antennas using the method of moments.

All the above applications are coded into software which can be bought and used but designing the sotware falls inside the remit of electrical engineering.

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If the determinant of the matrix of coefficients is non-zero then they are consistent.

More simplistically, if the lines representing the equations meet at a single point, the equations are consistent and if they don't, the equations are inconsistent. This is easy to check graphically in 2 and possibly 3 dimensions but not more. The determinant method always works.

A porthole is the 'window ' in a ship's cabin, usually round and with a very tough sealable window cover.

g (x) = -3x+5

-3x= 5

x= -5/3

To solve using matrices, you're usually given a set of 2 or more linear equations. Once you have that, isolate the variables and write numerically in the form of a matrix, dividing the right side from the left. Ex. : 2x + 3y = 7; 4x - y = 2 Isolating variables: [2 3 | 7]

[4 -1 | 2] From there onwards, it should be easy to solve.

4

Somewhat, but the rules are a bit different for inequalities. Example.

-2X > 4

X < - 2

See, sign changes when dividing by negative coefficient.

If you mean the graph, then the lowest coordinates would be (0,0).

Also known as the origin.

An expression does not have an equals sign, An equation has an equals sign,

Price of item without adding tax=152

Percentage of tax to be added=6%

To find the final price=

152+ 6%of 152

152+912/100

152+9.12

161.12

Hence the final price of the item is 161.12

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals".

It is not possible to work out what the equations are.

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Length.

The range of the function.

#include<stdio.h>

#include<conio.h>

main()

{

int a[4][4],b[4][4],c[4][4],i,j;

printf("enter the elements of matrix a");

for(i=0;i<=3;i++)

for(j=0;j<=3;j++)

scanf("%d",&a[i][j]);

printf("the first matris is");

for(i=0;i<=3;i++)

{

printf("\n");

for(j=0;j<=3;j++)

printf("%d",a[i][j]);

}

printf("Enter the elements of second matrix");

for(i=0;i<=3;i++)

for(j=0;j<=3;j++)

scanf("%d",&b[i][j]);

printf("the second matrix is");

for(i=0;i<=3;i++)

{

printf("\n");

for(j=0;j<=3;j++)

printf("%d",b[i][j]);

}

for(i=0;i<=4;i++)

for(j=0;j<=4;j++)

c[i][j]=a[i][j] + b[i][j];

printf("the addition of matrix is");

for(i=0;i<=3;i++)

{

for(j=0;j<=3;j++)

printf("%d\t",c[i][j]);

printf("\n");

}

getch();

}

5

If x^2 = 0, x = 0 Only 0^2 can equal 0.

Unless your "everyday life" involves work in some area of engineering, you won't use matrices in your everyday life.

cross: torque

dot: work

The solution is the coordinates of the point where the graphs of the equations intersect.

Straight lines are linear.

The correlation remains the same.

7x-4y = 26

5x-4y = 14

Subtract the bottom equation from the top squation remembering that a minus minus is equal to a plus therefore - 4y - - 4y = 0

2x = 12

Divide both sides by 2 to find the value of x:

x = 6

Substitute the value of x into the original equations to find the value of y:

Therefore: x = 6 and y = 4