Oxidation Numbers

The oxidation number of Hg in HgOH is +1. Mercury (Hg) typically has an oxidation state of +1 in compounds. Oxygen usually has an oxidation state of -2, so the oxidation state of Hg can be determined by setting up an equation and solving for x: x + (-2) = 0; x = +2.

The oxidation number of nitrogen in N2H5Cl is -2. This is because hydrogen is usually assigned an oxidation number of +1 and chlorine is usually assigned an oxidation number of -1. Therefore, the total oxidation numbers must add up to 0 since the compound is neutral.

Carbon is a pblock element. It shows -4 to +4 oxidation numbers.

2. The elctron configuratio of Cd is [Kr] 4d10 5s2

The oxidation number of Cu in CuHSO4 is +1. This is because the overall charge of the compound is 0, and the oxidation number of H is +1, S is +6, and O is -2. By calculating the total oxidation numbers and assigning x to Cu, you can solve for x to find that Cu is in the +1 oxidation state.

The oxidation number of C in FeCO3 is +4. This can be determined by assigning the oxidation number of +2 to Fe and -2 to each O atom, and then solving for C based on the overall charge of the compound.

In MgH2, since magnesium is always assigned a +2 oxidation state and hydrogen typically has a -1 oxidation state, the oxidation number of hydrogen in MgH2 is -1.

The oxidation number of Al in AlF3 is +3 because fluorine has an oxidation number of -1 and there are three fluorine atoms in AlF3. This results in a neutral compound with an overall charge of 0.

The oxidation number of phosphorus in PBr5 is +5. This is because bromine typically has an oxidation number of -1, and there are 5 bromine atoms in PBr5, making the overall charge of the compound neutral.

Water, or H2O is a free-standing neutral compound, so it's oxidation number is 0. Its atoms have oxidation number though. Hydrogen's oxidation number in water is +1, and oxygen's is -2.

Chlorine shows many numbers. It dhows +3 in here.

Persulphate = S2O82-

O.S. of S = +7

O.S. of O = -2

The oxidation number of bismuth can vary. In its most common form, such as in Bi(NO3)3, bismuth has an oxidation number of +3. However, bismuth can exhibit other oxidation states as well, such as +5 in BiO3.

The oxidation number of carbon is +4 in CCl4. Each chlorine atom has an oxidation number of -1, and since there are 4 chlorine atoms bonded to carbon, the total oxidation number must equal 0 for a neutral molecule.

It is in the first group. It shows only -1 number.

It is 5.

study island answer is +3 -2

The oxidation number of Cl in NCl3 is -1. Nitrogen typically has an oxidation number of -3 in nitrogen-containing compounds, so the overall charge of NCl3 must be 0, making the oxidation number of Cl -1.

The oxidation number of Al is +3.

MnO2 is called manganese IV oxide because manganese has a +4 oxidation state in this compound. The Roman numeral IV indicates that manganese is in the +4 oxidation state, where it has lost four electrons.

If you are referring to the nitrate ion, NO3-, the oxidation number of oxygen would be O2- and nitrogen would be N5+. If you are talking about nitrogen trioxide NO3, the oxidation number of oxygen would be O2- and nitrogen would be N6+.

Edit: Nitrogen trioxide does not exist in its free state.

The oxidation number of sulfur in H2S2O8 is +6. Each oxygen atom has an oxidation number of -2, and each hydrogen atom has an oxidation number of +1. By setting up an equation and solving for sulfur's oxidation number, you will find it to be +6.

+2 for Mg, +4 for C, -2 for each O in MgCO3

Oxidation numbers are very important in much of chemistry because many times atoms do lose or gain electrons. When this happens, they become ions.However, oxidation numbers are especially important when writing chemical formulas for ionic compounds.