Probability

50% or 3 out of 6.

There are two main methods: theoretical and empirical.

Theoretical: Is the random variable the sum (or mean) of a large number of imdependent, identically distributed variables? If so, by the Central Limit Theorem the variable in question is approximately normally distributed.

Empirical: there are various goodness-of-fit tests. Two of the better known are the chi-square and the Kolmogorov-Smirnov tests. There are others. These compare the observed values with what might be expected if the distribution were Normal. The greater the discrepancy, the less likely it is that the distribution is Normal, the smaller the discrepancy the more likely that the distribution is Normal.

P(A) = 4/52 or 1/13 or 0.077 and P(B) = 13/52 or 1/4 or .25.

The composite numbers on an ordinary cube are 4 and 6 so the probability of rolling a composite is 2/6 = 1/3

You must remove 12 socks to be sure of having a pair of Brown one

A 6-sided die has 6 possible outcomes. If each of the sides has a different number from 1 to 6, then the probability of getting any one number is 1/6 or 16.67%.

no, because lets say 1 equals 100% if there is a 1.5(150%) chance of sun today it means its happening no matter what but also 1 means it is guarantee it will be to so really it doesn't make a difference

The probability is 19/25 * 18/24 = 0.57

The probability is 1/4

8 in 12 for the greater than 3 case. (4, 5, 6, 7, 8, 9, 10, 11, 12)

6 in 12 for the even case. (2, 4, 6, 8, 10, 12)

9 in 12 for the combined case. (2, 4, 5, 6, 7, 8, 9, 10, 11, 12)

There is no secret: the procedures are well studied. However, it is important to know whether the events are independent or dependent.

The answer depends on how many cards are in the hand.

Roll of the Dice was created on 1995-08-01.

It is 1/18.

The answer depends on what the trial comprises. Since that is not defined, there can be no sensible answer.

If the sample size is less then 30 use the T table, if greater then 30 use the Z table.

A Leap year has 366 days. in which you have 52 weeks and 2 days.

the 2 days may be

sun,Mon

mon,Tue

tue,wed

wed,THu,

thu,Fri

FRi,SAT

sat,sun

so you have 7 options among which 2 u can choose..

so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7.

The probability of having either 53 Sundays or 53 Thursdays is 4/7.

The probability of getting a spade out of a full deck is 13/52 = 1/4.

Now, to get exactly one spade you have the following possibilities:

a. Spade first, then others: 13/52*39/51*38/50

b. Other, then Spade, then other: 39/52*13/51*38/50

c. Other, then other, then spade: 39/52*38/51*13/50.

Sum them up, and you get 3*13*39*38/(52*51*50) = 0.4385

To understand this best, please draw a tree.

The number of objects in the furthest right column of the tree will be your denominator.

The probability of drawing an Ace in a standard deck of 52 cards is 4 in 52, or 1 in 13, or about 0.07692.

50%

1/2

0.5

Yes.

Standard deviation is the variance from the mean of the data.

13.3%