No, the highest wattage bulb will have the lowest resistance.
If a fourth bulb were added in a similar way to the three existing bulbs, the resistance in the circuit would go up if the bulbs were series connected, and it would go down if the bulbs were parallel connected.
They can be connected to either supply. A bulb in series that fails, will cause all the other bulbs to go out. A bulb in parallel that fails, will have no adverse effect on the other bulbs in that circuit
The brightness of a light bulb is related to its power. In all electrical circuits, power is equal to Voltage*Current. Since the two bulbs are connected in series, they must have equal current. The voltage across any given element in a series circuit is proportional to its resistance, so whichever bulb has the higher resistance has a higher voltage and thus higher power and is brighter.
A Bulb can be connected in a series in such a way that the energy source which is applied want to flow equally across the bulbs connected in series. A Bulb has to knobes or holds in which we supply the power. Assume one knob as a positive voltage absorbing source and other has a negative voltage absorbing source. When we connected in such a way that we can apply the voltage continuously in which the bulb will blow easily. When two or more bulbs are connected in series like end of the knob of one bulb i.e., negative to the next positive of the next bulb in series and negative of second bulb to the positive of the third bulb. Then the voltage splits equally across the bulbs connected.
Two bulbs connected in parallel are brighter than two connected in series. The resistance of the circuit is lower, electrons can flow more easily.
Connecting light bulb is equivalent to connecting a resistance. If you have connected light bulb, there will be some voltage drop across it and your TV may not get sufficient voltage. However if resistance is not big enough, than it wont have any effect.
A: A BULB in parallel has available all the power that the source can supply. In series the power divide according to each bulb resistance.
Assuming the bulbs and the battery are the same, two bulbs connected in series will glow less brightly than one bulb.The two bulbs will split the voltage in half between them, making the total power, assuming constant resistance, one half. Since the bulbs have a positive temperature coefficient, the actual power will be slightly more than one half, between the two of them, or slightly more than one quarter each.
Yes. When the bulbs are connected in series, the voltage across each bulb reduces hence the brightness reduces too.
One bulb would be connected in series with the switch. Two bulbs in the circuit would be connected in parallel with each other and then they both would be both connected in series with the switch.
Bulbs that are connected in parallel would be the same brightness as a bulb on its own. If the bulbs were in series with other bulbs, then they would be dimmer. The voltage would drop across a series.
All the three would glow at the same instant.
When bulbs are connected in series, the voltage across each bulbs also gets divided and hence the light goes dim.
· to show the effect on a bulb if a resistance is connected in series with it in the circuit.
all light in series go out
As you add more bulbs to a series circuit that means that the bulbs are in series to one another, therefore the total resistance is the sum of the individual resistance of the bulbs. If you add bulbs of the same resistance,then the rate at which the resistance changes will increase in a constant manner provided the current source is not altered. For instance if the bulb you are using is rated 20v,60w, then the current passing via the bulbs in series is the square of the voltage divided by the power in this case the current is approximately 7amperes.
it depends on how the bulbs are connected....if it is connected in series,supply (ex 220/4)...in paralell conn the bulb voltage is same as supply(al 4 bulbs)
Parallel With a series connected Christmas lights, when one light bulb is damaged, all the bulbs won't light.
That depends on whether the bulbs are wired in series or in parallel.
because the switch is closed
the voltage across it is reduced, the voltage is shared with other bulbs
The total resistance of a circuit when bulbs are placed in series increases, and the power dissipated across the bulbs decreases. The increase of resistance, and the decrease of power, is, however, not mathematically what would be expected from a naieve perspective (linear for resistance, inverse squared for power) because the resistance of bulbs varies dramatically with temperature. A 40W bulb, for instance, would pull 500W if it operated at its cold resistance.
ANSWERwhen two bulb are connected in series their will not be any changeANSWERWhat other bulbs? This question doesn't make sense.Perhaps you are thinking of this: with two bulbs in series, each bulb only gets 1/2 of the energy (or voltage) that a battery makes available, so each bulb is much dimmer than just one bulb attached to the battery would be.
In parallel, each bulb will have full voltage applied across them. However, in series, the voltage across each bulb won't be the same as supply voltage. Thereby, bulbs connected in parallel will glow brighter.