depending on the amount of albino powder used in the mixture of the coconut oil, 7.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The answer is 6,31 moles Ag.
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Using your molar mass. 0.0001 grams silver (1 mole Ag/108 grams)(6.022 X 1023/1 mole Ag) = 5.58 X 1017 atoms of silver =====================
It depends on the atomic mass of a substance. To find out, divide the 1 by the atomic mass of the element (found on the periodic table), then multiply by 6.02*1023. Ag=(1/Am)*6.02*1023 Where Am=atomic mass of the element, and Ag=the number of atoms in a gram.
1 mole Ag = 6.022 x 1023 atoms Ag 4.4910 x 1023 atoms Ag x 1 mole Ag/6.022 x 1023 atoms Ag = 0.7468 mole Ag
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
Only two atoms: Ag and I.
Silver phosphate is Ag3PO4It has 3 Ag atoms + 1 P atom + 4 O atoms = 3+1+4 = 8atoms per molecule Ag3PO4
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
6.023*1023
The answer is 6,31 moles Ag.
76.2 mol Ag
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)