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1.81x10^24 atoms
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Approximately how many moles are in 300 grams of sulfur?
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
How many moles are in 300 grams of calcium sulfide?
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
How many moles in 300.0g S?
300 g sulfur is equivalent to 9,36 moles.
How many atoms are in 300 grams of gold?
The answer is 9,17233.1023 atoms.
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
Approximately how many moles are in 300 grams of sulfur?
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
How many millimoles are in 12g of sodium hydroxide?
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
How many grams of sodium chloride is in 0.40 moles?
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
How many moles are in 300 grams of calcium sulfide?
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
How many moles in 300.0g S?
300 g sulfur is equivalent to 9,36 moles.
How many moles in 300g of sulfur?
300 g sulfur is equivalent to 9,357 moles.
How many atoms are in 300 grams of gold?
The answer is 9,17233.1023 atoms.
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
3M sodium hydroxide?
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
How many atoms are present in 23.0 mol of Ti?
1 mol = 6,022 x 10^23 molecules of HI. So: 6,022E23 *0,3 = Your answer !
How many atoms of carbon are in 0.020 g of carbon?
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