For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel.
4.5 grams / 28.0 grams = .161 moles CO
weight = moles x atomic weight = 7.32 x 58.93 = 431.36 g
The molecular mass of carbon monoxide, CO is 12.0+16.0=28.0
Amount of CO = 1.23/28.0 = 0.0439mol
500 grams of CO is the equivalent of 17,85 moles.
The molecular mass of carbon monoxide is 28,01 g.
77.1g/28g=2.75 moles
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
382 g Co contain 6,482 moles.
26,3 g cobalt is equivalent to 0,446 moles.
0,83moles glucose are burned.
1,4 moles carbon monoxide are produced.
1,4 moles of CO are produced.
4,54 L of CO have 0,182 moles.
How many moles of atoms are contained in 382 g Co
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
The answer is 6,482 moles.
382 g Co contain 6,482 moles.
no
2,55 moles of the compound CO have 71,4 grams.
26,3 g cobalt is equivalent to 0,446 moles.
1,4 moles carbon monoxide are produced.
0,83moles glucose are burned.
Remember the equation Moles = mass(g) / Relative Atomic/molecular mass (Ar/Mr) moles = mass(g) / Ar/Mr The mass is 14 g The Mr for CO is:- From the Periodic Table Mass of C = 12 and mass of O = 16 12 + 16 = 28 Substituting moles(CO = 14g / 28 moles = 0.5 ( or 1/2 mole)