dissolve 26.075g KCL and make final volume 100ml. The final product will be 3.5M solution of Kcl
how many grams of calcium nitrate are needed to make a 500ml volume of a .5 molar solution
The answer is 7,5g.
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
The answer is 3,211 g.
I suppose that this solution doesn't exist.
93,31 g MgCl2 are needed.
58 milligrams of NaCl are needed.
302 g sucrose are needed.
124,9 g grams of ammonium carbonate are needed.
You need 9,008 g of glucose.
More than 91 grams of potassium nitrate for 100 mL water.
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
The sodium chloride mass needed is 292,2 g
Molarity = moles of solute/Liters of solution 3 M KBr = moles KBr/1 liter = 3 moles KBr (119 grams/1 mole KBr) = 357 grams needed
Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.
How many grams of KHP are needed to exactly neutralize 36.7 mL of a 0.328 M barium hydroxidesolution
The needed mass of sodium chloride is 29,22 g.
It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
The answer is 1,000 grams
The needed mass is 35,549 g.
~58.5 g ~58.5 g 58.443 g
how many milliliters of 2.25M NaOH is needed to make 125mL of 0.75M NaOH solution
A US pint is 473 grams. - An Imperial pint is 568 grams
Asked By Wiki User
Copyright © 2021 Multiply Media, LLC. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply.