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What would be the final temperature when 100 grams of water at 30 degrees c is mixed with 50 grams of water at 60 degree c?
Wiki User
∙ 9y ago
The key to solving this problem is that the heat lost by the warmer water is equal to the heat gained by the colder water. Knowing the relation Q = mc(change in T), this problem can be solved with algebra. Q is heat, m is mass in grams, c is the specific heat of water 4.184 J/ g C, and T is temperature. 100g * 4.184 J / g C * (x - 30 C) = 50 g * 4.184 J / g C * (60 C - x). The final answer should have x = to 40 degrees C.
Wiki User
∙ 9y ago
Wiki User
∙ 12y agoA two q's to 0 problem
q = mass*specifice heat*change in temp.
(100 g H2O)(4.180 J/gC)(Tf - 30 C) + (50 g H2O)(4.180 J/gC)(Tf - 60 C) = 0
distribute
(418Tf - 12540) + (209Tf - 12540) = 0
drop parentheses and add all together
527Tf - 25080 = 0
add 25080 to each side
527Tf = 25080
divide both sides by 527
Temperature final = 48 degrees Celsius
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Jaelynn Blake
How many joules of energy is needed to raise the temperature 20 grams of iron form 20 c to 50c
Wiki User
∙ 11y agoq(joules) = mass * specific heat * change in temperature
q = (20 grams)(4.180 J/gCo)(30o C - 25o C)
= 418 joules of absorbed energy
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Radiance
Q=m.c.(Temperature 2-Temperature 1)
Specific heat capacity of water = 4200 J/ Kg . o C
= 4.2 J/ g. o C
Q= 20 g * 4.2 J/ g. o C * 5
Q= 420 J
Wiki User
∙ 11y ago20degrees celsius
Wiki User
∙ 12y ago35
Wiki User
∙ 12y ago31.96
Rotsen Aohco
2.5
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One hundred twenty grams of metal at 88 degree Celsius is poured into a 70 grams insulated cup contains 250 grams of water at 16 degree Celsius.The final temperature of the mixture is 17.5 degree celc?
It is not possible to answer the question without information about the specific heat of the metal and of the cup.
What is the final temperature of the mixture if 100gram of water at 70temperature is added to 200gram of cold water at 10temperature and well stirred?
I'll assume here that by "70 temperature" you mean "70 degrees Celsius". Basically, you have to calculate the average temperature of all of the water in the mixture, which will be the final temperature once it's well stirred. The 200 grams of water at 10 degrees represent 2/3 of the total amount of water (300 grams), so thus, multiply 10 by 2/3 to determine their contribution to the final temperature. You will get 20/3. The 100 grams of water at 70 degrees represent 1/3 of the total amount of water, so multiply 70 by 1/3 to determine their contribution to the final temperature. You will get 70/3. When you add together the two temperatures you get 90/3, which is equal to 30. Therefore, the final temperature is 30 degrees Celsius.
Is 50 grams 96 degrees Celsius 148 meters or 259 liters a measurement of volume?
Liters measure volume. Grams are a measure of mass, degrees Celsius are a measure of temperature, and meters are a measure of length.
Is Temperature the flow of energy from warm matter to cool matter?
No, certainly not.Temperature is a measure of the average kinetic energy of the particles in a body. The temperature of a thing is how strongly the little bits of that thing are shaking about. If they shake hard enough, meaning that the thing is hot enough, they shake the bits apart, so that the thing melts or evaporates.If I take something hot and put it against something cold, then the shaking of the molecules of the hot matter jostle the molecules of the cold matter, passing on some of their energy. To us that is a flow of heat energy from the hot matter to the cold.Get that straight! It is a flow of energy, not of temperature, and the temperature is not the flow!But, you say, suppose I take 10 grams of water at 95 degrees and put them against 10 grams of water at 35 degrees, I will get 20 grams at 65 degrees, right? How does that differ from a flow of temperature?Temperature does not flow; heat does. I chose that example carefully to make it look like a flow of temperature. Think of a different example: suppose that we put 10 grams of mercury at 95 degrees against 10 grams of water at 35 degrees; then we would get the whole lot at just about 37 degrees instead of 65 degrees, because it takes about 30 times as much heat to increase the temperature of one gram of water by one degree as it takes to heat one gram of mercury by one degree.Now, what happened to that "flow of temperature"?Get the picture?Heat will flow until the temperatures are the same all right, but the heat still is the only thing that flows.But, you say, isn't the temperature itself the flow?No, because if I have water at 95 degrees and I don't have it touching anything at a different temperature, then there is no flow of heat (or energy, if you like; same thing in our examples) and yet the temperature stays at 95. If the temperature were the flow, then zero flow would mean zero temperature, right? And do we get zero temperature? Not a bit of it; we get 95 degrees!Is this helping you get it straight? If not, ask again.
What are the masses in grams of a 0.5 kg glass bowl and a 0.5kg iron pan that have a temperature of 68 degrees F when placed in freezer?
1000
What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
The temperature would be that of water's boilng point od 100 degrees
One hundred twenty grams of metal at 88 degree Celsius is poured into a 70 grams insulated cup contains 250 grams of water at 16 degree Celsius.The final temperature of the mixture is 17.5 degree celc?
It is not possible to answer the question without information about the specific heat of the metal and of the cup.
What is the final temperature of the mixture if 100gram of water at 70temperature is added to 200gram of cold water at 10temperature and well stirred?
I'll assume here that by "70 temperature" you mean "70 degrees Celsius". Basically, you have to calculate the average temperature of all of the water in the mixture, which will be the final temperature once it's well stirred. The 200 grams of water at 10 degrees represent 2/3 of the total amount of water (300 grams), so thus, multiply 10 by 2/3 to determine their contribution to the final temperature. You will get 20/3. The 100 grams of water at 70 degrees represent 1/3 of the total amount of water, so multiply 70 by 1/3 to determine their contribution to the final temperature. You will get 70/3. When you add together the two temperatures you get 90/3, which is equal to 30. Therefore, the final temperature is 30 degrees Celsius.
If 1200 calories of heat is added to 40 grams of water at 20 degree what will be the final temperature?
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
What is the final equilibrium temperature when 15 grams of milk at 22 degrees Celsius is added to 185 grams of coffee at 86 degrees Celsius?
If coffee and milk have the same thermal coefficient then: (15*22 + 185*86)/200 = 81 (81,2 rounded off due to significant digits)
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
What will the final temperature be if 688 calories of heat is released by 25 mL of water with an initial temperature of 80 degrees celsius?
Do some converting first. 688 calories (4.184 Joules/1 calorie) = 2878.592 Joules 25 ml of water = 25 grams q(Jolules) = mass * specific heat * (Temp. final - Temp. initial) 2878.592 Joules = 25 grams Water * 4.180 J/gC * (Temp Final - 80C ) 2878.592 Joiles = 104.5( Temp. Final) - 8360 11238.592 =104.5(Temp. Final) 107.55 Celsius Final Temperature ( call it 108 C )
how many grams iron will absorb 900 joules of heat and only change temperature by .2 degrees?
200 grams
A particular sample of iron requires 562 Joules to raise its temperature from 25 degreee Celsius to 50 degrees Celsius. What must be the mass of the sample of iron?
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
What is the total heat loss if you have 18 grams of aluminum and the temperature changes from 64 degrees Celsius to 48 degrees Celsius?
Approx 4974 Joules.
Is 50 grams 96 degrees Celsius 148 meters or 259 liters a measurement of volume?
Liters measure volume. Grams are a measure of mass, degrees Celsius are a measure of temperature, and meters are a measure of length.
