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7.184119315x10^-3
Jessa Lorenzana
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2.
The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl).
Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
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∙ 10y ago95.2 g/mole
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How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
To calculate the number of moles, first convert the volume of the solution from milliliters to liters by dividing by 1000 (20.0 mL = 0.020 L). Then, use the formula n = M x V to calculate the moles of MgCl2 in the solution. n = 0.800 mol/L x 0.020 L = 0.016 moles of MgCl2.
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
What is the mass of 9.40 moles of magnesium chloride MgCl2?
To find the mass of 9.40 moles of magnesium chloride (MgCl2), you multiply the molar mass of MgCl2 by the number of moles. The molar mass of MgCl2 is approximately 95.21 g/mol. Therefore, the mass of 9.40 moles of MgCl2 would be 895.54 grams.
In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?
2
In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?
MgCl2 would be the limiting reagent
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
How many atoms are n 4.0 moles of MgCl2?
MgCl2 is an ionic compound with the Mg2+ cation and the Cl- anion in a 1:2 ratio. In each formula unit of MgCl2 there are two Mg2+ and one Cl- ion. So in 4 moles of MgCl2 there will be 12 moles of ions.
How many moles are in 2 Na3PO4 3 MgCl2--Mg3PO42 6NaCl?
12 moles
How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
To calculate the number of moles, first convert the volume of the solution from milliliters to liters by dividing by 1000 (20.0 mL = 0.020 L). Then, use the formula n = M x V to calculate the moles of MgCl2 in the solution. n = 0.800 mol/L x 0.020 L = 0.016 moles of MgCl2.
How many moles are contained in 444 grams of magnesium chloride?
Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
What is the mass of 9.40 moles of magnesium chloride MgCl2?
To find the mass of 9.40 moles of magnesium chloride (MgCl2), you multiply the molar mass of MgCl2 by the number of moles. The molar mass of MgCl2 is approximately 95.21 g/mol. Therefore, the mass of 9.40 moles of MgCl2 would be 895.54 grams.
In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?
2
In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?
MgCl2 would be the limiting reagent
How many moles of MgCl2 are present in 90.0 mL of 0.200 M MgCl2 solution?
To find the number of moles, first calculate the moles of MgCl2 in 90.0 mL of 0.200 M solution: moles = volume (L) * molarity moles = 0.090 L * 0.200 mol/L = 0.018 moles Therefore, there are 0.018 moles of MgCl2 present in 90.0 mL of 0.200 M MgCl2 solution.
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
In the reaction MgCl2 plus 2KOH and 65532 Mg(OH)2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
