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For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel.

4.5 grams / 28.0 grams = .161 moles CO

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15y ago
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11y ago

weight = moles x atomic weight = 7.32 x 58.93 = 431.36 g

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10y ago

The molecular mass of carbon monoxide, CO is 12.0+16.0=28.0

Amount of CO = 1.23/28.0 = 0.0439mol

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7y ago

500 grams of CO is the equivalent of 17,85 moles.

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6y ago

The molecular mass of carbon monoxide is 28,01 g.

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14y ago

77.1g/28g=2.75 moles

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Q: How many moles of CO in 1.23g of it?
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