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How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
Wiki User
∙ 13y ago
M= moles in solution/liters
so plug in what you know
3.0M of KCl solution = moles in solution/ 2.0L
multiply both sides by 2.0L
moles solute = 1.5 moles KCl
so you need 1.5 moles KCl to prepare the solution
Wiki User
∙ 13y ago
Wiki User
∙ 13y ago447 g KCl
Molarity is moles of solute
liters of solution.
3.00M = x mol
2.00 L
6 mol KCl converted to grams (molar mass = 74.5 g/mol) is 447 g KCl, with sig figs.
Wiki User
∙ 14y ago(X volume )(2.00M KCl ) = (500 ml )(0.100M KCl )
= 25 milliliters
Wiki User
∙ 13y agomoles of KCl=molarity of KCl solution * volume of KCl solution=4.0*1.00=4.0 moles
Wiki User
∙ 11y agoThe answer is 66,18 mL.
Wiki User
∙ 10y ago1.0
Wiki User
∙ 10y ago25.0 mL
Wiki User
∙ 13y ago1.0 moles
Wiki User
∙ 13y ago4.0 moles
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