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How many moles of sodium hydroxide are in a 36.65g sample of NaOH?
Wiki User
∙ 6y ago
To find the number of moles of NaOH in a 36.65g sample, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40g/mol (sodium 22.99g/mol + oxygen 16.00g/mol + hydrogen 1.01g/mol). So, 36.65g ÷ 40g/mol = 0.9163 moles of NaOH.
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If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
You would have 1.5 moles of sodium hydroxide. This is calculated by dividing the mass of sodium hydroxide by its molar mass: 60 grams / 40 grams/mole = 1.5 moles.
What is the molarity of a 3 sodium hydroxide solution?
A 3 M sodium hydroxide solution means there are 3 moles of sodium hydroxide dissolved in 1 liter of solution.
What would be the total mass of sodium hydroxide?
The total mass of sodium hydroxide would depend on the amount you have. To calculate it, you would need to know the molar mass of sodium hydroxide (which is 40.00 g/mol) and the number of moles you have, which can be determined by weighing the sample and dividing by the molar mass.
How many moles in 20g of sodium hydroxide?
To determine the number of moles in 20g of sodium hydroxide, you need to divide the given mass by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). So, 20g NaOH / 40 g/mol = 0.5 moles of sodium hydroxide.
What is the balanced equation for sodium hydroxide and copper III chloride?
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
How many grams are in a 6.94 mole sample of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams per mole. Therefore, a 6.94 mole sample of sodium hydroxide would contain approximately 278 grams (6.94 moles x 40 grams/mole).
How many moles are there in 2.50 moles of sodium?
Sodium in its elemental form is just sodium metal, Na. Thus assuming that the sample of sodium is pure, there are 2.50 moles of sodium in a 2.50mol sample.
Determine the number of moles of sodium hydroxide produced when 2 moles of sodium and 3 mol of water react to form soduim hydroxide and hydrogen gas?
The balanced equation for the reaction is: 2Na + 2H2O → 2NaOH + H2 From the equation, 2 moles of sodium will produce 2 moles of sodium hydroxide. So, in this case, 2 moles of sodium will produce 2 moles of sodium hydroxide.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How many moles of sodium sulphate can be formed from two moles of sodium hydroxide?
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
You would have 1.5 moles of sodium hydroxide. This is calculated by dividing the mass of sodium hydroxide by its molar mass: 60 grams / 40 grams/mole = 1.5 moles.
What is the mass in grams of 25 mol of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
What is the molarity of a 3 sodium hydroxide solution?
A 3 M sodium hydroxide solution means there are 3 moles of sodium hydroxide dissolved in 1 liter of solution.
What would be the total mass of sodium hydroxide?
The total mass of sodium hydroxide would depend on the amount you have. To calculate it, you would need to know the molar mass of sodium hydroxide (which is 40.00 g/mol) and the number of moles you have, which can be determined by weighing the sample and dividing by the molar mass.
How many moles in 20g of sodium hydroxide?
To determine the number of moles in 20g of sodium hydroxide, you need to divide the given mass by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). So, 20g NaOH / 40 g/mol = 0.5 moles of sodium hydroxide.
What is the balanced equation for sodium hydroxide and copper III chloride?
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
If you have a sample of 4.25 g of strontium hydroxide SrOH2 How many moles of strontium hydroxide are there?
0.0349 mol
