H2C4H4O6(aq)+2OH−(aq)→C4H4O62−(aq)+2H2O(l)
H+ + OH- = H2O
H+ + oh- ---> h2o
Hf + oh- ---> f- + h2o
It will be a neutralization reaction and the products will be NaCl and H2O
The chemical equation is:Mg+ + 2 OH- = Mg(OH)2(s)
H+ + OH- = H2O
H+ + oh- ---> h2o
Hf + oh- ---> f- + h2o
It will be a neutralization reaction and the products will be NaCl and H2O
Fe3+ + 3OH- _____> Fe(OH)3
2NaCl + Zn(OH)2
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
The chemical equation is:Mg+ + 2 OH- = Mg(OH)2(s)
CH3COOH + NaOH --> CH3COONa + H2OOr better the ionic equation in water:CH3COOH + OH- --> CH3COO- + H2O[Na+ ions are left out of the equation because they don't take part in this reaction: it stays unchanged in solution]
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)