"0.10 percent NaCl" is a concentration of sodium chloride in a solution. There are a lot of ways of expressing concentrations, but they all describe "how much of this" is in "how much of that." Percentages, such as yours, is commonly used in marketable goods, while chemists, and medical people use different ones.
0.10 percent NaCl means that for every liter of water, there is 1 gram of salt (1000:1 part ratio). That is not much: a pinch in a little more than a quart.
This depends on the mass of sodium chloride dissolved in a known volume of water.
The molarity is 1,711.
The answer is 0,171 moles.
The answer is 0,17.
0,1 M NaCl is equal to 0,5844 g/L.
The molarity is 0,149.
The solute is sodium chloride.
molarity of 5% NaCl solution would be 1.25M.
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
Convert the 200 mol of water to kilograms of NaCl
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
The molarity is 6.
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
The density of sodium chloride is 2,165 g/cm3.
10 percent NaCl in distilled water is equivalent to 100 g/L NaCl.
suspended in a solution with the following composition: 10% NaCl, 10% glucose and 40% albumin.
This molarity is 3 M.
This concentration is min. 150 mmoles/L NaCl.