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First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
The pOH is 6,4.
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
pOH= -log(0.0025) this equals +2.6. The pH scale is reversed, so 14-2.6 = +11.4. 11.4 is the answer
pH + pOH =14
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
The pOH is 6,4.
It will have a pOH of 12. Because pH+pOH=14
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
pH + pOH =14
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
na+oh +25=53 ph+poh=2.3
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4