pH + pOH =14
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
pH plus pOH equals 14.
pOH= -log(0.0220M OH) pH=14-pOH pH=12.34242268
10.1
pH + pOH = 14. So pOH = 14 - 1.12 = 12.88 pOH = -log[OH-] [OH-] = 1.31 x 10-13 M
The pH and pOH are related to each other through the equation: pH + pOH = 14 If the pH of a solution is 3, we can find the pOH by rearranging the above equation: pOH = 14 - pH = 14 - 3 = 11 Therefore, the pOH of the solution is 11.
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
The pOH is 6,4.
It will have a pOH of 12. Because pH+pOH=14
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
pH + pOH =14
Just like pH is the negative log of [H+], pOH is the negative log of the [OH-].
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
1.8