n=c/v
n=3M/.25L
n=12 mol
m=Mxn
m=58.443 g/mol x 12 mol
m=701.3 g
n= mol
c=concentration
v=volume
m=mass
M= molar mass
Tylerops:
I don't agree with this answer. Molarity is defined as Moles/Liters. In other words Molarity is the concentration of a solution. In the above n= Concentration / Liters. That is equal to saying Moles=(Moles/liters)/ Liters. In the above question the concentration is (3 moles/ liter), or 3M.
Plus, how can it be possible to have 12 moles in 250ml when you only have 3 moles in each liter of the original solution?
Correct ANSWER:
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter.
You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L.
So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles. 58.443g/molNaCl x .75 moles = FINAL ANSWER 43.83225g NaCl, Sig Fig, 43.83gNaCl
Molarity = moles of solute/Liters of solution. ( 250 milliliters = 0.250 Liters )
1.5 M NaOH = moles NaOH/0.250 Liters
= 0.375 moles NaOH, or, with sigi figis right
0.38 moles NaOH
250 mL is 0.250 liter. By definition, each liter of a 5.00 M solution contains 5 moles of sodium hydroxide, and each mole of sodium hydroxide contains one mole each of sodium and of hydroxide ions. Therefore, the specified volume of the specified solution contains 0.250(5.00) or 1.25 moles of hydroxide ions, to the justified number of significant digits.
This molarity is 13 M; but this solution doesn't exist.
(3.25m)(.25l)=13.0m
0.25 moles
130mi
0.25 moles
1
It is 25 moles of Sodium Hydroxide (;
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
Molarity = moles of solute/liters of solution M = 10 mol NaOH/1 liter = 10 M -log(10 M) = -1 14 - (-1) = 15 pH sodium hydroxide
6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water. Cheers!
1
It is 25 moles of Sodium Hydroxide (;
Sodium in its elemental form is just sodium metal, Na. Thus assuming that the sample of sodium is pure, there are 2.50 moles of sodium in a 2.50mol sample.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
Molarity = moles of solute/liters of solution M = 10 mol NaOH/1 liter = 10 M -log(10 M) = -1 14 - (-1) = 15 pH sodium hydroxide
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water. Cheers!
0.0349 mol