I assume you mean grams of aluminum.
4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al)
= 9.2 X 1017 atoms of aluminum
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A mole is 6.022x1022. Therefore, 5.75x1024/6.022x1022 = 95.482323 moles (9.55 moles of Al).________________________________________________________________Source: e2020
1 mole Al = 6.022 x 1023 atoms Al 0.2mol Al x 6.022 x 1023 atoms Al/1mol Al = 1 x 1023 atoms Al (rounded to 1 significant figure)
1 mole Al ( and everything else ) is 6.022 X 10^23 atoms,so.... 6 mole Al (6.022 X 10^23/1 mole Al) = 3.61 X 10^24 atoms aluminum
5.75x10^24 atoms x 1 mole/6.02x10^23 atoms = 9.55 moles of Al
There are 13 atoms:1 Ca atom2 Al atoms2 Si atoms8 0 atoms.
27 g (or 1 mole) of al will have 6.023 x 1023 atoms So, 86.1 g will have (86.1 x 6.023 x 1023) / 27 = 1.92 x 1024 atoms Al
A mole is 6.022x1022. Therefore, 5.75x1024/6.022x1022 = 95.482323 moles (9.55 moles of Al).________________________________________________________________Source: e2020
By definition, 1 mole of anything is 6.022 x 1023 particles of that thing. So, 1 mole of Al = 6.022 x 1023 atoms Al 7.5mol Al x (6.022 x 1023 atoms Al/1mol Al)=4.5165 x 1024 atoms Al
1 mole Al = 6.022 x 1023 atoms Al 0.2mol Al x 6.022 x 1023 atoms Al/1mol Al = 1 x 1023 atoms Al (rounded to 1 significant figure)
1 mole Al ( and everything else ) is 6.022 X 10^23 atoms,so.... 6 mole Al (6.022 X 10^23/1 mole Al) = 3.61 X 10^24 atoms aluminum
1mol Al = 26.981538g Al1mol Al atoms = 6.022 x 1023 atomsConvert grams to moles.1g Al x 1mol/26.981538g = 0.04mol AlConvert moles to atoms.0.04mol Al x 6.022 x 1023 atoms/mol = 2 x 1022 atoms Al
1 mole Al = 26.98g/mol (atomic weight in grams)1 mole Al = 6.022 X 1023 atoms AlConvert 2.78g Al to moles.2.78g Al x 1mol Al/26.98g = 0.103mol AlConvert moles Al to atoms Al.0.103mol Al x (6.022 x 1023atoms/mol) = 6.20 x 1022 atoms Al
3.85 atoms Al (1 mole atoms Al/6.022 X 10^23) = 6.39 X 10^-24 moles aluminum ( though 3.85 atoms seems unlikely )
7 atoms
5.75x10^24 atoms x 1 mole/6.02x10^23 atoms = 9.55 moles of Al
Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?The sample of______ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.16 moles of S to atoms of S:atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol SMultiply by atoms per mole. Moles cancel out.The sample of Al contains 8.18E+23 atoms.Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.
1. You think probable to the atoms of chemical elements. 2. Al l atoms of the same chemical element have the same atomic number.