0
If a resistor has a current of 2 amperes when connected to a single battery, connecting a second identical battery in parallel with the first will not change the current through the resistor.
This is because the voltage across the resistor will not change. Yes, the current capacity of the battery (pair) will double, but the voltage will not change.
The exception is if the battery does not have the capacity to supply 2 amperes without sagging in output voltage. In this case, adding the second battery will slightly increase the current through the resistor.
(By the way, without some kind of equalizing circuit, it is not a good idea to connect batteries in parallel. This is because slight differences in voltage could create substantial current flows through the batteries, and possibly damage, fire, and/or explosion.)
Wiki User
∙ 14y ago
Wiki User
∙ 11y agoif your in Mr.millers?Mrs.Dickson 1st hour this is harry and i don't know either
Wiki User
∙ 12y agoResistance is measured in ohms, not in amperes.
Once you get the correct data, apply Ohm's law: V=IR (voltage = current x resistance).
Wiki User
∙ 10y agoI2R...2*2*10=40 watts
Wiki User
∙ 16y ago5 ohms
Add your answer:
Earn +20 pts
What happens to the current flowing in a circuit if its resistance is doubled?
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
What is the resistance of a short circuit in ohms called?
Your original question was in two parts:1.) How many ohms in an open circuit? Infinite ohms (the meter will show no measurement).2.) How many ohms in a short circuit? 0 ohms. There would be no measurable ohms as there would be no resistance in the altered circuit.
What is meant by the term short circuit?
When a wire is cut in a circuit, a gap is made and the current can no longer circulate, known as an open circuit.When 2 parts of a circuit touch, that shouldn't, for example - a wire comes loose and comes into contact with another part of the circuit, its shortening the route of the current in the circuit. So its a short circuit. When this happens 99.9% of the time the result will be a spike in amp's, so tripping any circuit protection, MCB's, fuses.A good example of a common short circuit is faulty windings on a 3-phase electric motor. If the resin separating the windings becomes damaged it can cause 2 or even 3 of the motors phases to come into contact causing the motors overload protection to trip.
A circuit with 20 ohms of resistance and a current flow of 20 amps will use 6000 watts of power is this true?
P=I^2*R. No. 8,000 watts.
What happen to the parallel circuit if one resistance is removed?
assume the following configuration: battery connected to 2 parallel resistors with an ammeter in series with the battery... observe the current measurement ... remove one of the resistors .... observe the current again, it will have decreased: if the resistors were of equal value, the current will decrease to half of its original value when one of the resistors is removed. Mathematics: V=IR (V- voltage, I - current, R - resistance in a parallel circuit, R=(R1*R2)/(R1+R2) where R1 and R2 are the values of resistance of the resistors. Before removal- Ib=V*(R1+R2)/(R1*R2) After removal (assume R2 is removed)- Ia=V/R1 so Ia/Ib=(R1*R2)/(R1*(R1+R2)) or Ia=Ib*(R2/(R1+R2) if R1=R2 then Ia=Ib*R2/(2*R2) or Ia=Ib/2 so the current after is 1/2 of that before.
What is the affect of a series circuit on current?
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
What is the current in a 10v circuit if the resistance is 2?
If we apply Ohm's law, which is E = I x R and we have a voltage (E) of 110 volts and a current (I) of 10 amps, we can use the variation of the formula to solve. That variation is R = E / I and the resistance (R) is discovered by dividing the voltage by the current. R = E / I = 110 / 10 = 11 ohms
What is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts?
Use the formula: P=IR (power = current x resistance).
In series circuit is currant change with change in resistance?
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
Why is there no flow of electric current?
There are two possible causes: 1. The circuit has no Voltage applied to it. 2. The resistance of the circuit is INFINITE.
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
How is total resistance in a series circuit determined?
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
What is the power of a ciruit with 10 ohmns 10 volts and 2 amps?
Well, first of all, if the resistance of the circuit is 10 ohms and you connect 10 volts to it,then the current is 1 Amp, not 2 . So either there's something else in your circuit thatyou're not telling us about, or else the circuit simply doesn't exist.-- If you connect some voltage to some resistance, then the resistance heats up anddissipates (voltage)2/resistancewatts of power, and the power supply has to supply it.-- If there is some current flowing through some resistance, then the resistance heats up anddissipates (current)2 x (resistance)watts of power, and the power supply has to supply it.-- If there's a circuit with some voltage connected to it and some current flowingthrough it, then the resistance of the circuit is (voltage)/(current) ohms, the partsin the circuit heat up and dissipate (voltage) x (current) watts of power, andthe power supply has to supply it.There's no such thing as "the power of a circuit". The power supply supplies thecircuit with some amount of power, the circuit either dissipates or radiates someamount of power, and the two amounts are equal.
Is electric circuit also called series circuit?
The 2 simplest Electrical circuits areSeries Circuit - Same amount of current running through loads but voltage various by the resistance of the loadsParallel Circuit - Same voltage on the different loads by subject to the load resistance, the current passing through is different
How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?
Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.The divider will be composed of 4 resistors starting at the 10VDC rail:2VDC drop, ratio = 2V/10V = 0.23VDC drop, ratio = 3V/10V = 0.33VDC drop, ratio = 3V/10V = 0.32VDC drop, ratio = 2V/10V = 0.2Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.But as stated at the beginning you can get no further without additional requirements being specified.
In a circuit with a 6 V battery hooked up to a 3 Ohm light bulb what does the current measure?
2 amperes (current = voltage/resistance)
How will a current change if the resistance of a circuit remain constant while the voltage across the circuit decreases to half its original value?
Voltage = resistance X current abbreviated,V = C * RIf you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:(1/2)V=(1/2)(C*R)which is the same as:(1/2)V=(1/2)(C)(R)which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.
