What is the total resistance of a 3 ohm resistor and a 6 ohm resistor in parallel?

Answer 1

R = 1/[1/2 + 1/4 + 1/6 + 1/10]

Add up the reciprocals of the resistances, and take the reciprocal of the answer.

Answer 2

Always less then the lowest resistor value.
Calculate: 1/R = 1/ra + 1/ rb +1/rc +1/rd

ie. 1/R = (1/2) + (1/4) + (1/6) + (1/10)

= 0.5000 + 0.2500 + 0.1667 + 0.1000

= 1.0167

So R = 1 / 1.0167 = 0.9836 ohm

Answer 3

It's the reciprocal of the sum of 1/3, 1/6, 1/10, and 1/30.

(1/3) + (1/6) + (1/10) + (1/30) =

(10/30) + (5/30) + (3/30) + 1/30) = (19/30)

So the net effective resistance is (30/19) ohms.

Answer 4

The idea is to use the formula: 1/R = 1/R1 + 1/R2 + 1/R3..., which is simple and fairly easy to remember.

In other words:

1) Calculate the reciprocal of each resistance.

2) Add those reciprocals up.

3) Take the reciprocal of the result in step (2), to get the equivalent (or total) resistance.

Quick check: the final result should be less than any of the individual resistances.

Answer 5

The total resistance of a 30 ohm resistor in parallel with a 20 ohm resistor is 12 ohms.

1 / (1/30 + 1/20)

Answer 6

9 ohms.

It is as simple as adding the resistance together.

However, if they were inparallel, you would need to use ohms law.

Answer 7

2 ohms. (3*6)/(3+6)

Answer 8

1/(1/70 + 1/40 + 1/30) = 13.778