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NaN3 also known as Sodium azide is used as an antibacterial agent and to inflate airbags.
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∙ 13y ago
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What is the main gas in an air bag that inflated using the NaN3 reaction?
NaN3 decomposed to form nitrogen gas (N2) and sodium. 2NaN3 --> 2Na + 3N2
How many moles of N2 are produced by the decomposition of 1.20 mol of NaN3?
The number of atoms is 45,166.10e23.
What does Land use in geography mean?
Land use is defined as how the area is used. Such as for recreational use, farm use, industrial use etc.
What are the four basic parts of a use case model?
use case identifier, use case actors ,use case model,use case diagram
When you use your senses do you use a chemical change?
No if you use your senses it is a physical change
What is the chemical formula for sodium azide?
NaN3
What is the empirical formula for sodium azide?
NaN3
What is the main gas in an air bag that inflated using the NaN3 reaction?
NaN3 decomposed to form nitrogen gas (N2) and sodium. 2NaN3 --> 2Na + 3N2
What is the name of this compound NaN3?
Sodium Nitride
What is sodium azide?
Sodium azide is a chemical compound with the formula NaN3.
What gas fills air bags?
Callod sodium acid ( NaN3 )
How many moles of N2 are produced by the decomposition of 2.88 mol of sodium azide?
2NaN3 --> 2Na + 3N22.88 mol of NaN3 reacted * (3 mol of N2 produced / 2 mol of NaN3 reacted) =4.32 mol of N2
What is the structure of Sodium Azide - NaN3?
Its structure is like: Na-N=N=N
How is sodium azide decomposed?
The chemical equation is:2 NaN3 = 2 Na + 3N2
How many grams of NaN3 are required to from 6.00 g of N2 gas?
9.28 g
How much sodium azide is used in airbags?
Between 50 g and 250 g of NAN3.
How many grams of NaN3 are required to produce 13.0 ft3 of nitrogen gas if the gas has a density of 1.25 gL?
13.0 cubic feet is equivalent to .3681 cubic meters, which is equivalent to 368.1 liters. At 1.25 grams/liter, there are 460.1 grams. Nitrogen gas has a molar mass of 28.0134 g/mol, so there are 16.4 moles of N2. The equation for the decomposition of NaN3 is 2 NaN3 --> 2 Na + 3 N2. So, for every 3 moles of N2, there must have been 2 moles of NaN3, hence there was 10.9 moles. With a molar mass of 65.01 g/mol, there were 709 grams of NaNO3 to begin with.
