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Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?

The sample of _____ contains the greatest number of atoms.

Answer:

In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.

The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / mol

To convert 5.18 moles of I to atoms of I:

atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol I

Multiply by atoms per mole. Moles cancel out.

The sample of Mn contains 3.29E+24 atoms.

Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.

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Q: Which sample contains the greatest number of atoms a sample of Mn that contains 3.29E plus 24 atoms or a 5.18 mole sample of you?
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