This question needs clarification, because "formula units" can mean either the number of atoms to constitute one formula or Avogadro's Number of such formula units, although the latter should more precisely described as "gram formula units".
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
To determine the number of formula units in 2.45 moles of potassium chloride, you first need to find the molar mass of KCl, which is approximately 74.55 g/mol. Then, divide the number of moles by the molar mass to get the number of formula units. Therefore, 2.45 moles of KCl is equivalent to about 163 formula units.
To calculate the number of moles, you first need to find the molar mass of zinc phosphate (Zn3(PO4)2), which is approximately 386.11 g/mol. Then, use the formula: moles = number of formula units / Avogadro's number. Plugging in the values, you get moles = 5.546 X 10^37 formula units / 6.022 X 10^23 mol^-1, which equals approximately 9.22 X 10^13 moles.
To find the moles of formula units in 5.67 g of iron III sulfate, you first need to calculate the molar mass of Fe2(SO4)3. The molar mass is 399.9 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 5.67 g / 399.9 g/mol = 0.0142 moles of formula units.
To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.
10 formula units
The answer is 5,978 moles.
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
The answer is one mole.
1337
The answer is 32,4.10e23.
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
42.394 grams.
The answer is 2,09 moles.
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
(2.3 x 10^23) / (6.02 x 10^23) =0.38 moles
To determine the number of formula units in 2.45 moles of potassium chloride, you first need to find the molar mass of KCl, which is approximately 74.55 g/mol. Then, divide the number of moles by the molar mass to get the number of formula units. Therefore, 2.45 moles of KCl is equivalent to about 163 formula units.