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How many grams 3 of HF?
The molar mass of HF (hydrofluoric acid) is 20.01 g/mol. Therefore, 3 moles of HF would be equal to 60.03 grams.
How many grams are 4.5 moles of NH3?
Here is the solution,for 1mole NH3 or ammonia,N: 14.0067 g/mol x 1H: 1.00794 g/mol x 3So approximately it is--> 17.03052 g/mol)Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g
How many moles of HF will react completely with 12.5 mol of SiO2?
The balanced equation for the reaction between HF and SiO2 is: 6 HF + SiO2 -> H2SiF6 + 2 H2O. Therefore, each mole of SiO2 reacts with 6 moles of HF. So, 12.5 mol of SiO2 will react with 12.5 mol x 6 = 75 mol of HF.
How many moles of HF are needed to react with 0.220 mol of Na2SiO3?
The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits. __________________________ The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.
If a 20.0g sample of HF is dissolved in water to give 200mL of solution what is the concentration of this solution?
concentration = molarity molarity= moles/ volume (in liters) H=1g F= 19g 1gH+ 19gF= 20gHF 20gHF x (1 mol HF/ 20gHF) = 1mol HF 2.0x10^2ml= 200ml x (1L/1000mL)= .200L Concentration= 1 mol HF/ .200L Concentration= 5M
How many grams of HF are needed to make 0.50 l of a 0.750 m solution?
To prepare a 0.750 m (molal) solution, you need to know the mass of the solvent (in kg) because molality is defined as moles of solute per kg of solvent. For a 0.50 L solution, assuming the solvent is water with a density of approximately 1 g/mL, you have 0.50 kg of water. Thus, for 0.750 m, you need 0.750 moles of HF. The molar mass of HF is about 20.01 g/mol, so you would need 0.750 moles × 20.01 g/mol = 15.01 grams of HF.
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass in grams of 0.330mol of calcium?
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
What is the mass of 0.45 mol of ammonium sulfate?
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
What is the mass of a sample containing 5.82 mol of zinc?
378.3g You multiply the RMM by the Concentration (mol) Mass(g)=Concentration(mol)*RMM
