0
How many watts will be dissipated by a 30 ohm resistor with 12 volts applied?
Wiki User
∙ 11y ago
P = IV
Where: P = power in watts, I = Current, and V= Voltage
Using ohms law: V = IR where V=Voltage, I = Current, and R= Resistance
First solve for I,
I = V/R, 12/30 = .4
Then use the power equation:
P = .4*12 = 4.8 Watts
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What applied voltage will cause a 20 Ω resistor to dissipate 5 Watts?
10V
What is the power dissipated by a 10 ohm resistor with 20 volts supply?
A 10 ohm resistor across a 20 volt source has 2 amps flowing through it. A 20 volt source providing 2 amps is producing 40 watts. Voltage is Resistance times AmperesWatts is Voltage times AmperesAlternative AnswerDivide the square of the voltage by the resistance.
How much power is dissipated by a circuit with 15000 ohms of resistance and 10mA of current?
15 KOhms times 10 mA = 150 volts. 150 volts times 10 mA = 1.5 watts.
How do you reduce 48 volts dc to 12 volts dc with resistors?
Yes. You can use a voltage divider. Say, for instance, one 1KOhm resistor in series with a 3KOhm resistor. Connect the 3k resistor to the 48 volts and connect the 1k resistor to ground. The 1k resistor will have 12 volts acress it. These resistors need to be at least 1 watt each as they are going to dissipate 0.576 watts and get warm. Now, if you attempt to pull power from the 1k resistor, note that regulation will be poor because the impedance of the load will go in parallel with the 1k resistor and change its value.
How much power will be dissipated by a 9 ohm resistor if 9 volts are applied across it?
P = (E2)/R = 81/9 = 9 watts
What is the power dissipated by a resistor that has 5 amps flowing through it with 120 volts applied?
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
What is the Power dissipated from a 0.5A current through a 5ohm resistor?
The current I = 0.18257 amperes. Scroll down to related links and look at "Electrical voltage V, amperage I, resistivity R, impedance Z, wattage P".
How do you determine the amperage given the voltage and power dissipated?
Like Ohm's Law, the formula for calculating power is a simple product of two quantities. It is given by the formula P = VI, where V is the voltage in volts and I is the current in amperes (or simply amps). So, if you know the value of any two of the quantities, you can easily calculate the third with simple arithmetic. For example, if the current flowing through a resistor is two amps and the voltage drop across that resistor is five volts, the power dissipated by the resistor is, P = VI = 5 volts * 2 amps = 10 watts. If you are given the power and the voltage, you can easily find the current. For example, if you are told that the voltage drop across a resistor is five volts and is dissipating 10 watts, the current through the resistor is 10 watts/5 volts = 2 amps.
What is the current running through a resistor of 9 ohms with volts of 90?
I = E / RIf the voltage across the resistor is 90 volts, and the resistance of the resistoris 9 ohms, then the current through the resistor is90/9 = 10 Amperes.Don't try this at home!The power dissipated by the resistor is E2/R = (90)2/9 = 900 watts. That's comparable to the power (heat) dissipated by a small toaster. A common composition resistor will get hot and possibly explode if it's asked to dissipate that kind of power.
What power is dissipated by an 8.2 k resistor if a current of 0.005 amps pass's through the resistor?
.205 watts or 205 mw
Calculate the resistor in a circuit having 12V source voltage and power dissipation of 10 W?
0.069444444444444444444444444444444444 ohms. P/E^2=R. P = power in watts. E = electricity in volts. R = resistance in ohms.
Calculate the Power in watts dissipated by a resistor of 1000 ohms with 200 volts across it 2 watts 20 watts 40 watts 400 watts?
Ohms law states that V = I * R I = V/R R = V/I P = I*V Where V = Voltage, I=Current, R = Resistance and P = Power or Watt Watt is the amount of electricity flowing through a line which is (Voltage times Current in (Amperage) = Power or watts) To find the power dissipated by a resistor of 1000 ohms, we first find the current I. The voltage is given as 200volts. Therefore I = V/R = 200/1000 = 0.2Amps We said Power or Watt = I*V Therefore the Power or watts dissipated by a resistor of 1000 ohms will be P=I*V = 200*0.2 = 40 Watts
What is the Power dissipated allowed by a circuit breaker with 208 volts and 5 amps?
1,040 watts or 1.04 KW.
Calculate the power used in 2ohm resistor in each what circuits- 1 a 6V battery in series wid 1ohm and 2ohm resistors 2 a 4V battery in parallel wid 12ohm and 2ohm resistors?
1). 6V battery, 1-ohm resistor, 2-ohm resistor, all in series:Total resistance = 3 ohms.Current in the loop = 6/3 = 2 amperesPower dissipated by the 2-ohm resistor - I2R = 8 watts.2). 4V battery, 12-ohm resistor, 2-ohm resistor, all in parallelThe 12-ohm resistor is irrelevant.4 volts across the 2-ohm resistor.Power dissipated by the 2-ohm resistor = E2/R = 8 watts.
Cause of burnout of two resistor?
Too much current flowing in circuit. Sounds like a voltage was applied that exceeded the rating of the resistor. Resistors are rated in watts which is Volts times Amps. As an example, you might have a 1/2 watt rated resistor. If you applied 120 VAC across a 10 Ohm resistance then the current would be 12 Amps. The wattage would be 1,440 watts which is well in access of the rating and would certainly burn out the resistor.
What is the power dissipated by a resistor with a current of 0.02 A adn a resistance of 1000 ohms?
Power dissipated = I2R 0.022 x 1000 = 0.4 watts
