answersLogoWhite

0


Best Answer

A 12 ohm resistor with 6 volts across it will dissipate 3 watts of power.

Current = voltage divided by resistance = 6 / 12 = 0.5 amperes.

Power = voltage times current = 6 * 0.5 = 3 watts.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

14y ago

Volts = Amps (i) X Resistance (or Impedence in AC)

Here I = 6 volts/12 ohms = 0.5 Amps

Power= Amps (I) X Volts

Power = 0.5 X 6 Volts

Power = 3 Watts

This answer is:
User Avatar
User Avatar

Isaac florence

Lvl 1
10mo ago
Thank you for the answer but it is not the one I am looking for.

User Avatar

Wiki User

11y ago

You first have to know the voltage that is going to be submitted to. Then the power

that will dissipate will be given by: P = V2/R

This answer is:
User Avatar

User Avatar

Wiki User

16y ago

It will depend on the voltage u apply..... It can be calculated as.... V/12 ; V is the voltege that u apply... Regards; Sujay; http://sujay00.blogspot.com

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

power = voltage x current = 24 volts x 2 amperes = 48 watts

power = current2 x resistance = (2 amperes)2 x 12 ohms = 48 watts

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

P = E2 / R = 3,600 / 620 = 5.8065 watts(rounded)

This answer is:
User Avatar

User Avatar

Anonymous

Lvl 1
4y ago

48 watts

This answer is:
User Avatar

User Avatar

Anonymous

Lvl 1
3y ago

3 watts

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How much power will be dissipated by a 12 ohm resistor if 6 volts are applied across it?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about General Science

What is series connection?

You have two resistors, each with resistance of 12Ω, and a 12-volt battery. 1). The resistors are in series across the battery. ..... A. voltage across each resistor ..... B. current through each resistor ..... C. power dissipated by each resistor ..... D. total power delivered by the battery 2). The resistors are in parallel across the battery. ..... A. voltage across each resistor ..... B. current through each resistor ..... C. power dissipated by each resistor ..... D. total power delivered by the battery ============================================ 1). ... A. 6 volts ... B. 0.5 Amp ... C. 3 watts ... D. 6 watts 2). ... A. 12 volts ... B. 1 Amp ... C. 12 watts ... D. 24 watts


Calculate the resistor in a circuit having 12V source voltage and power dissipation of 10 W?

0.069444444444444444444444444444444444 ohms. P/E^2=R. P = power in watts. E = electricity in volts. R = resistance in ohms.


Can you measure the physical size of a resistor to determine its wattage?

there might be ways to get the power rating by measuring the size of the resistor. but as the physical size of the resistor increases, its power rating also increases..


If a circuit has a voltage drop of 60.0 V across a 120.0 resistor that carries a current of 0.500 A. What is the power conducted by the resistor Use P VI.?

Well, if the question says "use P = VI", just do it! You have the values of voltage (V) and current (I) right there.


What is the scientific meaning of power?

Power is defined as the rate at which energy is used,generated, moved, converted, or dissipated.

Related questions

What process will double the power dissipated by a resistor?

Increase the voltage across the resistor by 41.4% .


How much power will be dissipated by a 9 ohm resistor if 9 volts are applied across it?

P = (E2)/R = 81/9 = 9 watts


What power is dissipated if 800v is applied across a 10 ohm resistor?

The power dissipated by a 10 ohm resistor with 800v across it is 64 kw.Ohm's law: current is voltage divided by resistancePower law: power is voltage times current, so power is voltage squared divided by resistanceDon't even think about trying this. 64 kw is a lot of power. The resistor will probably explode, or catch fire. At best, the 80 amps required will trip your circuit breaker, if you are lucky.


How Determine the power dissipated by the resistor?

Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).


What is the power dissipated by a resistor with a current of 2 amps and a resistance of 1000 ohms?

I = 2A R = 1000Ω Power Dissipated P = I2R = (2A)2(1000Ω) = 4000W Voltage across resistor V = IR = (2A)(1000Ω) = 2000V


A 100 ohm resistor is placed across a 100v power source what is the power?

Power dissipated in a resistance = E2/R = (100)2/100 = 100 watts.


At what level will typical resistors burn out?

A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor


What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?

There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.


2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?

No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.


Voltage drop of 15 Volts across 2.7 killo ohm resistor?

You just stated that the voltage across the resistor is 15 volts, so that's your answer ! If the resistor is connected to a 15-V battery or to the output of a 15-V power supply, then a meter across the resistor is also across the power supply, and reads 15 volts. The current through the resistor is (V/R) = (15/2700) = 5.56 mA. The power dissipated by the resistor (and delivered by the battery) is (V2/R) = (225/2700) = 0.083 watt.


What is the current through the 150 ohm resistor?

It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).


Ac power that is converted to heat in a resistor is known as?

real power (as opposed to imaginary power, which is not dissipated)