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2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
What would happen to the power dissipated in the voltage divider?
The power dissipated in a voltage divider circuit is given by the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance of the resistor. If the resistance in the voltage divider circuit is increased, the power dissipated in the circuit will decrease. This is because as resistance increases, the current flowing through the circuit decreases, leading to less power being dissipated as heat in the resistors.
What is the power dissipated in the Ohm resistor?
Power dissipated is always Volts times Amps. W= V*I because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value; W= V^2/R or W= I^2*R.
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
What power is dissipated by an 8.2 k resistor if a current of 0.005 amps pass's through the resistor?
.205 watts or 205 mw
What is the formula for calculating the power dissipated in a resistor, given the current flowing through it and the resistance value, known as the i2r power?
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
At what level will typical resistors burn out?
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
How can joule law be demonstrated experimentally?
Joule's law can be demonstrated experimentally by using a setup where electrical energy is converted into heat energy as current flows through a resistor. By measuring the voltage across the resistor and the current passing through it, the power dissipated as heat (P = I^2 * R) can be calculated. The increase in temperature of the resistor due to the heat generated confirms Joule's law.
Ac power that is converted to heat in a resistor is known as?
real power (as opposed to imaginary power, which is not dissipated)
What is the current running through a resistor of 9 ohms with volts of 90?
I = E / RIf the voltage across the resistor is 90 volts, and the resistance of the resistoris 9 ohms, then the current through the resistor is90/9 = 10 Amperes.Don't try this at home!The power dissipated by the resistor is E2/R = (90)2/9 = 900 watts. That's comparable to the power (heat) dissipated by a small toaster. A common composition resistor will get hot and possibly explode if it's asked to dissipate that kind of power.
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What is the power dissipated by a resistor with a current of 2 amps and a resistance of 1000 ohms?
I = 2A R = 1000Ω Power Dissipated P = I2R = (2A)2(1000Ω) = 4000W Voltage across resistor V = IR = (2A)(1000Ω) = 2000V
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
