First determine what voltage is needed for phase to phase. Where you work on or where the gears are coming from would help to answer this question. In Southeast Asia, where power is 220~240 volts, a 3 phase system would be 415v phase to phase. In North America, a 3 phase system would be 208v phase to phase. So now you know the voltage that you are working with on a 3 phase system. Next use this formula, kVA x 1000 / voltage required / 1.73 = amp 3 phase Example, you have a 60kVA generator. And you working in North America, which is 208v phase to phase. 60 kVA x 1000 / 208 v / 1.73 = 166amp 3 phase Written by: Rony Xu Hope this helps!
KVA is the unit for the apparent power i.e it's the vector sum of the true power in KW and the reactive power in reactive volt-amperage. So, to get the value of the KVA for the 30KW,just divide the active power(30kw) with the power factor of that load.
3 phase kVA = V*I*sqrt(3) Where voltage is line to line, and current is the actual RMS current flowing in the a wire. kW = V*I*sqrt(3)*Cos (phi), where phi is the angle between the voltage and current; Cos (phi) is also known as the power factor. kVA is the vector sum of kW (real power) and kVAR (reactive power). As the equations above suggest, you must know the voltage to correctly calculate the current.
The same way, as you convert Appels to Carrots ........... There is a formula: KVAr = KVA / KW or cos=KW/KVA > Yes, we are treating KW, KVA, & KVAr as the 3 sides in a 90 deg TRIANGLE ! KW= vertical katede KVAr = horizontal katede KVA = hypotenuse
The voltage and current will give the kVA, but the kW depends on the power factor of whatever load is connected to the supply. For a (let's say) 11 kV supply, the voltage from line to neutral is 11,000/sqrt(3) which is 6351 v. The kVA on each phase is 6.351 times the current, and you just add up the three kVA values to find the total. At higher voltges like 11 kV the three currents in the lines are usually very nearly equal.
Full load amps for a three phase, 375KVA generator is 375 / (voltage in kV) / sqrt(3).
KVA is the unit for the apparent power i.e it's the vector sum of the true power in KW and the reactive power in reactive volt-amperage. So, to get the value of the KVA for the 30KW,just divide the active power(30kw) with the power factor of that load.
KW is multiplication of KVA and power factor. Power factor is load dependent and varies as per the type of load. Hence the rating or capacity is mentioned in KVA not in KW
3 phase kVA = V*I*sqrt(3) Where voltage is line to line, and current is the actual RMS current flowing in the a wire. kW = V*I*sqrt(3)*Cos (phi), where phi is the angle between the voltage and current; Cos (phi) is also known as the power factor. kVA is the vector sum of kW (real power) and kVAR (reactive power). As the equations above suggest, you must know the voltage to correctly calculate the current.
The same way, as you convert Appels to Carrots ........... There is a formula: KVAr = KVA / KW or cos=KW/KVA > Yes, we are treating KW, KVA, & KVAr as the 3 sides in a 90 deg TRIANGLE ! KW= vertical katede KVAr = horizontal katede KVA = hypotenuse
The voltage and current will give the kVA, but the kW depends on the power factor of whatever load is connected to the supply. For a (let's say) 11 kV supply, the voltage from line to neutral is 11,000/sqrt(3) which is 6351 v. The kVA on each phase is 6.351 times the current, and you just add up the three kVA values to find the total. At higher voltges like 11 kV the three currents in the lines are usually very nearly equal.
The answer: 17070 BTU The math: 3414 BTU = 1 KVA (KW) so 5 KVA = 17070 BTU
Full load amps for a three phase, 375KVA generator is 375 / (voltage in kV) / sqrt(3).
Total KVA of the transformer divided by (square root of 3 times the voltage). This will give the individual phase currents. These individual phase currents will be 120 degrees out of phase with each other.
Va=volts x amps. The K stands for one thousand. So 1 Kva is one thousand watts. So 415v times 120a= 49,800 what's. You divide that by a thousand and you get 49.8. So it would be 49.8 Kva.
22 x 277 x 3 or 1.73 x 480 x 22 or more accurately: 22 x 277.1283 x 3 = 18.29 kW or 1.7320508 x 480 x 22 = 18.29 kW ---------------------------------------------------------------------------- Theory: S = Va Ia* = |Va| | Ia| = {|Vab| / }| Ia| = S Thus, S3 = 3 S = 3 {|Vab| / }| Ia| = |Vab| | Ia| ------------------------------------------------------------------------------- S = Va Ia* = |Va| | Ia| and S3 = 3 S ; 22 x 277.1283 x 3 = 18.29 kW or |Vab| | Ia| = 1.7320508 x 480 x 22 = 18.29 kW
The formula is that kW^2 + kVAR^2 equals kVA^2 or if you prefer, the kW and the kVAR are the two sides of a right angled triangle and the kVA is the hypotenuse. So here you have a 3-4-5 triangle times 140, in other words 420-560-700, and the kVAR is 420.
A typical tea urn would take 2-3 kW and the kVA would be the same.