Because the lone pair of electron of nitrogen in case of Aniline becomes involve in resonance process of aromatic ring and is less available for the attack of an acid.
NH3 (ammonia) is less stable than water due to its lower boiling point and reactivity with acids. Water is a more stable molecule due to its strong hydrogen bonding and overall lower reactivity compared to ammonia.
Pyridine is more basic than aniline primarily due to the presence of the nitrogen atom in a sp² hybridized aromatic ring in pyridine, which allows it to donate its lone pair of electrons more effectively. In contrast, aniline's nitrogen is part of an amine group attached to a benzene ring, where the lone pair is partially delocalized into the aromatic system, making it less available for protonation. This delocalization in aniline reduces its basicity compared to the more localized lone pair on the nitrogen in pyridine.
The aniline point of kerosene is 60-69 oC.
At 20o C aniline's rate of solubility in water is 3.6g/mL. So, aniline mixes with water unlike kerosene which forms a layer above the water. Separating funnel is used to separate two immiscible liquids and cannot separate miscible liquids. Hence, we cannot separate water and aniline using separating funnel.
In ammonia (NH₃), nitrogen has five valence electrons and needs three more to achieve a stable outer shell, while each hydrogen atom has one valence electron. The nitrogen atom shares its three valence electrons with three hydrogen atoms, forming three covalent bonds. This sharing allows nitrogen to attain a full outer shell with eight electrons (including the shared ones), while each hydrogen achieves a stable configuration with two electrons through the shared bonding. Thus, all atoms in ammonia gain stable outer shells through these covalent interactions.
Aniline is less basic than ammonia because the nitrogen lone pair on aniline is partially delocalized into the benzene ring, making it less available to accept a proton. Ammonia, on the other hand, has a more localized lone pair on nitrogen, which is more readily available for protonation.
aniline is more acidic because in aniline a electron withdrawing benzene is connected.electron withdrawing capacity of benzene is due to its delocalizing pi electrons cloud.due the action of benzene the presence of unshared pair of electron over nitrogen is somehow decreases.which increases its acidic nature. But in case of ammonia there is no electron withdrawing group.so its unshared pair of electron remains undistrubed,which decreases its acidity and increases its basisity
Ammonia is a stronger base than aniline because the lone pair on the nitrogen in ammonia is more readily available for donation compared to the nitrogen in aniline, which is partially delocalized due to resonance. As a result, ammonia is able to more effectively accept a proton to form its conjugate acid, making it a stronger base.
Aniline is a weaker base than ammonia because the lone pair on the nitrogen atom in aniline is partially delocalized into the benzene ring, making it less available for donation to form a bond with a proton. In contrast, the lone pair on the nitrogen atom in ammonia is more readily available for donation, resulting in a stronger basicity.
NH3 (ammonia) is less stable than water due to its lower boiling point and reactivity with acids. Water is a more stable molecule due to its strong hydrogen bonding and overall lower reactivity compared to ammonia.
NH3 (ammonia) is more stable than NH4 (ammonium) because ammonia is a neutral molecule, while ammonium is a positively charged ion. Generally, neutral molecules are more stable compared to charged ions due to lower electrostatic repulsion.
Strength of bases is related to the ease of accepting a proton which inturn depends on the availability of electron pair on the nitrogen atom (or some other basic atom). More is the availability of electron pair, more easily the proton will be accepted and more will be the basic strength.Aniline is a weaker base than ammonia or cyclohexylamine. It is because of the fact that the electron pair on nitrogen is involved in delocalization, making it less available for donation.
if clorine is mixed with amonia.. Cl2 + NH3 ---> NH4Cl It is much stable but the mixture of sodium hypoclorite and aqua amonia is not much stable...
Yes, it decomposes at about 950 Celsius.
There is likely no reaction, aniline is a base that upon aquiring a proton converts to a stable ammonium cation, ferric nitrate( Fe(NO3)2 ) has no protons to donate to the amine group of aniline means it will likely not react. In addition the nitrate ion of ferric nitrate is the conjugate base of Nitric acid and is thus extremely stable isn't likely to react with much of anything.
Amines are organic compounds that contain nitrogen. They are derived from ammonia (NH3) by replacing one or more hydrogen atoms with alkyl or aryl groups. Examples include methylamine, ethylamine, and aniline.
Because in Benzylamine : the unshared lone pair of electron on nitrogen atom isavailable >.. But in n-ethyl aniline: the unshared lone pair of electron is not available and enter resonance with benzene ring .(Villa)