Probability

Suppose A is the event {rolling a 6-sided die 20 times and getting a 5}

Then A', the complement of A, is the event {rolling a 6-sided die 20 times and not getting a 5 any times}

So Pr(A) = 1 - Pr(A') = 1 - (5/6)20 = 1 - 0.026084 = 0.973916 (to 6 dp)

The answer is 8,648,640 in 674,274,182,400 or approximately 0.128%.

To pull seven spades in a row from a deck of 52 cards may be translated as follows:

In a deck of 52 cards there are 13 spades, so 13 chances to pull a spade or 13/52.

After pulling one spade, there are 12 spades left and 51 cards left, so 12 chances to pull a spade or 12 / 51.

After pulling the second spade, there are 11 spades left and 50 cards left, so 11 chances to pull a spade or 11 / 50.

Continuing the above logic to the natural conclusion, we get the following multipliers:

13 / 52 * 12 / 51 * 11 / 50 * 10 / 49 * 9 / 48 * 8 / 47 * 7 / 46

which is equal to 8,648,640 / 674,274,182,400 or approximately 0.128%.

The probability of rolling 4 and 4 on a single roll of two dice is 1 in 36. You don't have to count. The probability of rolling 4 on one die is 1 in 6. The probability of rolling two 4's is (1 in 6) squared or 1 in 36. If you insist on counting, go ahead, 11, 12, 13, 14, 15, 16, 21, 22, 23, 24, etc. You will find 36 combinations, with only one 44 in them, hence 1 in 36.

THe answer will depend on whether the confidence interval is central or one-sided. If central, then

-1.28 < z < 1.28

-1.28 < (m - 18)/6 < 1.28

-7.68 < m - 18 < 7.68

10.3 < m < 25.7

He is supposed to be the king ceaser. who was one eyed. He had lost one eye during the war.

The 8 possible outcomes for three children are:

* ggg

* ggb

* gbg

* gbb

* bgg

* bgb

* bbg

* bbb

Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.

Since 48 cards of a 52-card deck are not aces, you are guaranteed to have at least two aces only if you have at least 50 cards.

Since there are four suits for each rank, you are guaranteed to have at least two ranks whenever you have at least five cards.

Scott Duff has a book that is very good.

Everything is a lot to ask for on the computer, so I suggest you follow the above advice and read the book, but here are a few highlights. Like most inventors, John Garand was somewhat eccentric. The Garand rifle was originally chambered for the .276 Pederson cartridge, but Doug MacArthur was Chief of Ordinance in the 30's and he decreed (wisely in my opinion) that all US rifle-caliber weapons be 30-06, reducing the M-1 Garand's capacity from ten to eight rounds. The M1903 sling was also compatible with the Garand, and the US ammo pouch accepted the 8-round Garand clips as easily as the 5-round M1903 clips. The M-1 Garand was adopted by the US Army in 1936 but produced in small numbers. In 1941 the Garand rifle beat the Johnson rifle and the M1903 as the USMC rifle. After the US entered the war, production could not keep up with demand, and an M-1 Garand was not in the hands of every American rifleman until 1943-44, although the M1903 continued for sniping and grenade-launching. The Germans had a semi-automatic rifle called the Gewehr 43 which was a good semi-automatic weapon, but simply was not as reliable and robust as the M1 (due to being made of crude parts and machining from mass supply shortages) nor was it as easly to produce or mantain in the field as the Garand rifle, so it was used mostly as a sniping rifle instead of a battle rifle, even then, it was very rare to encounter since it was never mass produced. The M-1 rifle fought again in Korea with the US and other armies, and it was replaced by the the M-14 in 1956. The US M-14 and the Italian BM59 are near-copies of the M-1 Garand in operation, but firing the smaller .308 Winchester cartridge.

The probability that a coin will land on heads - at least once - in six tosses is 0.9844

It means the event is certain to happen.

• heights of people
• size of things produced by machines
• errors in measurements
• blood pressure
• marks on a test

The number of ways that the letters B-R-O-N-X can be arranged is the same as the number of permutations of 5 things taken 5 at a time, which is 5 factorial, or 120.

The odds are 50/50. A tossed coin does not have a memory.

7/26

that it is a marble? 1. Unless I have lost my marbles.

Assuming the numbers are 1-6, the probability is 0.

1 in 2, or 0.5

1 in 12

About 6

There is no relationship between sequences and probability.

The 4 letters can be arranged in 24 different sequences.

No, we can't expression any negative value as a probability. A probability ranges from 0 to 1 - 0 being the lowest and 1 being the highest.

0.1972

The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...

The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...

The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...

The answer depends on what the experiment is: drawing a card, rolling a die, with a spinner, ...