Probability

... most easily if you have some knowledge of the subject,

for example by having studied it.

75 over 2^23 (2 times itself 23 times, 2x2x2x2x2 etc...)

First white = 10/20

second white = 9/19

third white = 8/18

fourth white = 7/17

firth white = 6/16

Total probability = 10/20 x 9/19 x 8/18 x 7/17 x 6/16

= 21/1292

~= 0.0163

4, one in each suit (Hearts, Diamonds, Spades, Clubs.)

The mean absolute deviation is the sum of the differences between data values and the mean, divided by the count. In this case it is 15.7143

something that some people believe that in 2012, the world will end.

is that what your trying to ask?

No, the normal curve is not the meaning of the Normal distribution: it is one way of representing it.

The question cannot be answered properly because the children's genders are not independent events. They depend on the parents' ages and their genes. Furthermore, it is often wrongly assumed that the probability of a boy is 50%. That is simply not true: the latest information shows that the probability of a boy is 52%.

However, if you choose to ignore reality then the solution, based on the Binomial(9, 1/2) distribution, is that the probability is 0.1641, approximately.

No, the probability of an outcome can't be more than 1.

The probability of getting curly hair depends on whether your parents do or not. Hair genes are decided by the mother. So, if the mother has curly hair, more than likely the offspring will as well. If the father has curly hair and the mother does not, the probability is considerably lowered.

If the first and second C are indistinguishable, then there are 554,400 permutations. If one is upper case and the other is lower case, then there are twice as many.

20 * 19 * 18 * 17 = 116,280 ways

This is Permutation: nPr = n! / (n-r)!

Simple question, difficult answer. It depends on how many times you want the penny to land on heads. The probability of a penny landing on heads once is 1 in 2. For it to land on heads twice is 1 in 4, for three times it is 1 in 8, and so on and so forth.

250

Here's how:

1. Add the ratio: 7 + 5 = 12

2. Divide the total no. of marbles (600) by 12 = 50

3. The total no. of reds = 7 x 50 = 350

4. The total no. of blues = 5 x 50 = 250

(Total blues & reds = 350 + 250 = 600)

You can either determine the probability through fractions. ( i.e: a coin has only two sides, if flipped it will be either heads or tails; the outcome will be 1/2 to happen: so equal chance of either. )

However, you can also determine it by how likely something is to happen, e.g: if it is winter it is likely it will rain, yet in summer it is unlikely to rain.

Possible outcomes are HH, HT, TH, TT; therefore the probability of HH is 1/4 or 0.25.

A set of probabilities over the sampling distribution of the mean.

It is 6/26 = 3/13

No matter how many coins are thrown, the possibility of having AT LEAST ONE 'head' is 50%. This changes if you specify the number of 'heads' that must be shown.

In a typical die, there are six sides, so you know that there are six different possible outcomes when you roll it. In this problem, it asks for the probability of either 5 or 6 showing up. To find this simply add 1/6 to 1/6 or multiply 1/6 by 2. Either method will give you the answer of 2/6 which can be simplified to 1/3.

1/2 or .50. Of the 52 cards, 26 are either a heart or a diamond (there are 13 hearts, 13 diamonds, 13 clubs and 13 spades).

That will depend on how much foreskin you have. My foreskin used to retract upon erection until I did some foreskin stretching. Now, at this point, the foreskin remains over the glans, with just the meatus showing. I plan on stretching more to achieve total coverage in all states of erection. See the sites available on the web regarding foreskin restoration. Although I am intact, I still chose to lengthen the foreskin to achieve the coverage when erect.

If you pick it up, there is a 99% chance that you will roll the dice upon dropping it, and a 1% chance of it landing on one face and sitting there, not rolling.