Probability

If it lands on a six 140 times then the estimated probability of a six is 140/400 = 0.35

6/16 = 3/8

The probability is 4/36 = 1/9

For theoretical reasons (such as the central limit theorem), any variable that is the sum of a large number of independent factors is likely to be normally distributed. For this reason, the normal distribution is used throughout statistics, natural science, and social science as a simple model for complex phenomena.

I am a 2nd and not a junior. I have the same name as my Grandfather. If I were to have the same name as my father I would be a junior. If I give my son the same as myself he would be a junior and a 3rd.

Standard deviation of a single event is 0.

Pretty slim in the US or most of Europe and Asia. If you are in Africa or the Middle East you would have a significantly higher risk. Still relatively small though, you're much more likely to die in a car acccident than from a random gunman.

The probability of observing a z value equal to or more extreme than 1.50 is 0.1336

It is 1/6.

A 'random' sample - covers all age groups, genders, and other criteria. A 'targeted' sample might only cover a small part of the population.

Your risk of getting pregnant is the same as any other time when you are fertile. Unless you are menopausal or pregnant, you have a chance of becoming pregnant from having sex.

13 out of 52.

_____________________

It should be 20 out of 52 if Ace is included as a number card.

Not including ace the probability is 18 out of 52.

1 out of six for both five and six well that's for the original die wich is 1 of each number from 1 to 6 it depends how many sides it has

The probability of drawing a king or a nine from a standard deck of 52 cards is (4 + 4) in 52, or 8 in 52, or 2 in 13, or about 0.1538.

About 98 percent.

one of each suit = four total

The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations.

The answer is 24 and this is how:

A b c d

A b d c

A c d b

A c b d

A d c b

A d b c

B c d a

B c a d

B d a c

B d c a

B a c d

B a d c

C d a b

C d b a

C a b d

C a d b

C b d a

C b a d

D a b c

D a c b

D b c a

D b a c

D c a b

D c b a

Assuming that the chosen are over the age of 85, the probability is

(0.28)8 = 0.000038

Probability is a number in the range [0, 1]. The question gives a probability (240) which is way outside this range and so is not valid.

if the confidence interval is 24.4 to 38.0 than the average is the exact middle:

31.2, and the margin of error is 6.8

someone without legs :3

37 because they are increased by consecutive odd numbers each time.

The mean alone is not enough to provide an answer.

No, the opposite is true.