1

low

By "the nth term" of a sequence we mean an expression that will allow us to calculate the term that is in the nth position of the sequence. For example consider the sequence 2, 4, 6, 8, 10,... The pattern is easy to see. # The first term is two. # The second term is two times two. # The third term is two times three. # The fourth term is two times four. # The tenth term is two times ten. # the nineteenth term is two times nineteen. # The nth term is two times n.

In this sequence the nth term is 2n.

That's the average value of all the members of the set.

There cannot be a counterexample since the assertion is true.

This requires you to accept the true fact that the terminating decimal 1.25, for example, is equivalent to the repeating decimal 1.25000... (or even 1.24999.... ).

Rational and irrational numbers are real numbers.

A complex number is represented by a+bi where a and b are real numbers.

Zero is a real number therefore any real number is also complex whenever b=0

macros

I think the following Wikipedia link on Fourier Series (see related links below), has the information that you're looking for.

I would go for the blue that is for example aqua blue

Imaginary numbers are useful in describing how waves (such as electrical signals) relate and interact with one another. The picomonster website in the related link has one of the coolest explanations, along with animations, that I've seen.

If the coefficient of i is not zero then the number is not real.

Yes even without the 0 figure

Yes and no.

That is the correct answer because dealing with infinity sometimes is nonsense.

For every even number there are two whole numbers (an even and an odd).

But if we count on - to infinity - we have ∞ (infinity) even numbers.

That means we have 2 * ∞ whole numbers.

But 2 * ∞ = ∞ (because we are dealing with infinity)

So, there are as many whole numbers as even numbers, eventhough there are twice as many.

it means stay still but i hate the patriots

associative process

There are no real reason why it is denoted by z, but that the real number axis is denoted by x, imaginary number is denoted by y, the real part of a complex number is denoted by a, the imaginary part of a complex number is denoted by b, so there is z left.

to untouched or mixed ;just one.

Multiply the numerator and denominator by the complex conjugate

of the denominator ... [ root(2) minus i ].

This process is called 'rationalizing the denominator'.

Let the number be x:-

So: 1000 > x < 1002

Your question is ill-posed. I have not come across a comparison dense-denser-densest.

The term "dense" is a topological property of a set:

A set A is dense in a set B, if for all y in B, there is an open set O of B, such that O and A have nonempty intersection.

The rational numbers are indeed dense in the set of real numbers with the standard topology. An open set containing a real number contains always a rational number.

Another way of saying it is that every real number can be approximated to any precision by rational numbers.

There are denser sets, if you are willing to consider more elements.

Suppose you construct a set consisting of the rational numbers plus all algebraic numbers. The set of algebraic numbers is also countable, but adding them, makes it obviously easier to approximate real numbers.

Can you perhaps construct a set less dense than the set of rational numbers?

Suppose we take the set of rational numbers without the element 0. Is this set still dense in the real numbers? Yes, because 0 can be approximated by 1/n, n>1.

In fact, you can remove finite number of rational numbers from the set of rational numbers and the resulting set will still be dense in the set of the real numbers.

Shut tup you lezza 0121 do one

140 multiplied by 2

28 multiplied by 10

There are many more ways to multiply to get 280.

To add complex numbers, the real parts and the imaginary parts are added separately. For example, to add (3 + 3i) + (5 - 2i), the result is (3+5) + (3-2)i = 8+i.

Subtraction is quite similar - you subtract the real and the imaginary parts separately. For example, (3 + 3i) - (5 - 2i) = (3-5) + (3 - -2)i = -2+5i.

"no solution"