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Probability
The probability of a certain event is a number expressing the likelihood that a specific event will occur, expressed as the ratio of the number of actual occurrences to the number of possible occurrences. In mathematics, it is a measure of how often an event will happen and is the basis of statistics.
14,643 Questions
Oh, dude, let me break it down for you. So, since the first digit can't be 0 or 1, we have 8 options for that first digit. After that, we have 9 options for the next digit, then 8 for the next, and so on. So, it's like 8 x 9 x 8 x 7 x 6 x 5 x 4. Crunch those numbers and you get the total number of 7-digit phone numbers that can be formed without repeating any digits.
What is the probability of 6 any numbers in lottery of 40 numbers?
Assuming there are six numbers drawn out of the set from 1 to 49, without replacement:
There are 15 out of 49 of these numbers that are prime. So the probability would be
(15 - 9)! / (49 - 43)! = (15 * 14 * 13 * 12 * 11 * 10) / (49 * 48 * 47 * 46 * 45 * 44)
= (24325271111131) / (27335172111231471) = (5 * 13) / (8 * 3 * 7 * 23 * 47)
= 65 / 181608
What are the odds of sinking 8 ball on the break twice in a row?
The odds of sinking the 8 ball on the break in a standard game of pool are typically around 1 in 40. To calculate the odds of sinking it twice in a row, you would multiply the probability of sinking it once (1/40) by itself, resulting in a probability of approximately 1 in 1,600. This means that the chances of sinking the 8 ball on the break twice in a row are quite low.
How many black aces are there in a deck of 52 cards?
In a standard deck of 52 cards, there are two black aces: the Ace of Spades and the Ace of Clubs. These two cards are the only aces that are black in color, as the other two aces (Ace of Hearts and Ace of Diamonds) are red. So, there are two black aces in a deck of 52 cards.
How many ways can you arrange the letters in the word prime?
Since no letters are repeated in the word prime, you can arrange the letters in the word prime 5! ways, or 120 ways.
What is the probability of getting 6 numbers in a lottery of 40 numbers?
Think of watching the lottery draw. You have 6 numbers and there are 40 to draw from.
On the first pick, you have a 6/40 chance of getting a match.
If you're successful, then on the second pick you have a 5/39 chance on the next pick (because one number is gone from your card and the draw), and so on.
Because all of the events are required to happen for you to get your 6 numbers, we multiply the individual probabilities together to get the overall probability.
6/40 x 5/39 x 4/38 x 3/37 x 2/36 x 1/35 = 1/3838380
So the chance of getting all six numbers is a little better than 1 in 4 million.
How ways cam you arrange a 4 letter word Adam?
If you have 4 DIFFERENT letters, there are 24 ways - this is equal to 4! (that is, the factorial of 4). Because of the two repeated letters, if you do this, you get every valid combination repeated twice (i.e., by exchanging one "a" with the other "a" you get an identical combination). Therefore the real number of arrangements is only one-half that value.
How many red 2's are in a deck of cards?
A standard deck of cards contains 52 cards, which includes 4 suits - hearts, diamonds, clubs, and spades. Each suit has one red 2, specifically the 2 of hearts and the 2 of diamonds. Therefore, there are two red 2's in a deck of cards.
Well, honey, if 80% of California drivers wear seat belts, then the probability of one driver wearing a seat belt is 0.8. So, the probability of all three drivers wearing their seat belts would be 0.8 x 0.8 x 0.8, which equals 0.512 or 51.2%. So, there you have it, buckle up and enjoy the ride!
What are the chances of rolling doubles 7 times in a row?
The probability of rolling doubles on a fair six-sided die is 1/6. To roll doubles 7 times in a row, you would need to multiply this probability by itself 7 times, resulting in (1/6)^7. This equals approximately 1 in 78,364,164,096, which means the chances of rolling doubles 7 times in a row are extremely low.
What is the probability of getting an ace or a joker from a pack of 54 cards?
Well, isn't that a happy little question! In a pack of 54 cards with 2 jokers, you have 4 aces and 2 jokers. So, you have a total of 6 cards that are either aces or jokers. To find the probability, you simply divide the number of favorable outcomes (6) by the total number of outcomes (54). So, the probability of drawing an ace or a joker is 6/54, which simplifies to 1/9. Happy painting!
How do you make a maths working model on triangles for school exhibition of class 9th?
Oh, what a delightful project to work on! To make a math working model on triangles for your school exhibition, you can start by gathering materials like cardboard, markers, and a ruler. Then, you can create different types of triangles such as equilateral, isosceles, and scalene using the materials. Remember to label each triangle and showcase their unique properties to help your classmates understand them better. Just remember, there are no mistakes in art or math - only happy little accidents!
What is the probability of drawing 2 hearts in a deck of cards?
The probability of drawing the two of hearts is 1/52.
The probability of drawing two cards that are hearts depends on whether or not the first card is replaced.
If it is replaced, then the probability is (1/4)*(1/4) = 1/16 = 0.0625
while if it is not, the probability is (1/4)*(12/51) = 3/51 = 0.0588 (approx).
Pam is playing with red and black marbles?
Well, isn't Pam just living life on the edge with those red and black marbles? I hope she's not planning on starting a game of roulette anytime soon. Just be careful, Pam, those marbles can be a slippery slope to a high-stakes game of chance.
How many possible outcomes if you toss a coin four times?
- all heads
- all tails
- 3 heads 1 tail
- 3 tails and 1 head
- 2h and 2t
i think only 5 but that's just what i can get
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The above answer is correct if you disregard the order of the outcomes.
If the order of the outcomes matters, then the answer is:
2 x 2 x 2 x 2 = 16
since each toss has two possible outcomes (assuming the coin cannot land on its side) and you repeat the toss four times.
There are 84 different combinations possible for the committee of 6, taken from
4 students and 5 teachers.
1.- The committee with 4 students has 4C4 number of combinations of 4 students out of 4 and 5C2 number of combinations of 2 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 4 students and 2 teachers.
2.- The committee with 3 students has 4C3 number of combinations of 3 students out of 4 and 5C3 number of combinations of 3 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 3 students and 6 teachers.
3.- The committee with 2 students has 4C2 number of combinations of 2 students
out of 4 and 5C4 number of combinations of 4 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 2 students and 4 teachers.
4.- The committee with 1 student has 4C1 number of combinations of 1 student out of 4 students and 5C5 number of combinations of 5 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 1 student and 5 teachers.
We now add up all possible combinations:
4C4∙5C2 + 4C3∙5C3 + 4C2∙5C4 + 4C1∙5C5 = 1(10) + 4(10) +6(5) + 4(1) = 84
There are 84 different combinations possible for the committee of 6, taken from
4 students and 5 teachers.
[ nCr = n!/(r!(n-r)!) ]
[ n! = n(n-1)(n-2)∙∙∙(3)(2)(1) ]
What is the experimental probability of rolling a 2 on a number cube rolled 50 times?
Conduct the following experiment:
Roll a number cube 50 times.
Count the number of times you roll a 2.
Divide that number by 50.
That is the experimental probability.
The answer that I might get may well be different to yours. And if you do you experiment another time, the answer is likely to be different.
To create five numbers that are multiples of 5 using the ten cards numbered 0 to 9, you can arrange them as follows:
- Use the cards 0, 5, 6, 7, and 8 to form the number 5,687 (multiple of 5).
- Use the cards 0, 1, 2, 5, and 9 to form the number 9,521 (multiple of 5).
- Use the cards 0, 3, 4, 5, and 8 to form the number 8,543 (multiple of 5).
- Use the cards 0, 2, 5, 6, and 7 to form the number 7,652 (multiple of 5).
- Use the cards 0, 1, 4, 5, and 9 to form the number 9,541 (multiple of 5).
What is the probability to choose a prime number from numbers 1 to 50?
Well, honey, there are 15 prime numbers between 1 and 50. So, the probability of choosing a prime number from that range would be 15 (prime numbers) divided by 50 (total numbers), which simplifies to 3/10 or 30%. Math doesn't have to be boring, darling!
The chance of receiving a blue result is 2 in 4, in other words 50%.
Well, honey, there are 11 marbles in total, and 4 of them are blue. So, if you don't want a blue marble, that leaves you with 7 marbles to choose from. The probability of picking a marble that is not blue is 7/11. Hope that helps, sugar!
