Probability

Assuming it is a regular 6 sided die, it would be 4/6 or 2/3.

1/3 or 4/12

Assuming you mean random variable here.

A random variable is term that can take have different values. for example a random variable x that represent the out come of rolling a dice, that is x can equal 1,2,3,4,5,or 6.

Think of probability distribution as the mapping of likelihood of the out comes from an experiment. In the dice case, the probability distribution will tell you that there 1/6 the time you will get 1, 2,3....,or 6. this is called uniform distribution since all the out comes have that same probability of occurring.

Within each stratum it is, but overall, it is not.

When it is random it is variable.

1/2 if it is a fair coin

Yes. Probability can be expressed i

n fractio

ns.

We can't answer that without knowing what else is in the bowl.

Let say the dice has n sides

Let first search for the probability to roll a number less or equal to 2

Probability to roll a 1 = 1/n

Probability to roll a 2 = 1/n

Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2

= 1/n + 1/n = 2/n

Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2)

= 1 - 2/n = (n-2)/n

If n = 6 then the result is (6-2)/6 = 4/6 = 2/3

I've never heard of it but i have thought about it before. i mean it can be vaporized so im sure it can be condensed. the confusing part is that it is a solid. i came up with a design and that would be to hook up a THC vaporizer to a bottle filled with everclear. put the hose from the vaporizer in the bottle, so the vaporized THC would bubble up through it. you would have to make sure the alcohol is cold enough to condense it quickly. then evaporate the alcohol and you would have somewhat pure THC (i believe its a white powder when its pure.) using this method you can eliminate the other substances that are alcohol soluble but don't vaporize.

Zero, or, actually, so close to zero that for all practical purposes you can consider it to be zero.

2222

1/4

9:10

If the coin is fair and balanced, like Fox, then the probability is 50%.

They are simply convenient notations. In fact, in binary, 10 is two.

5/12

Consider the possibile outcome of two rolls of a die (where order matters):

(1,1)

(1,2)

(1,3)

.

.

.

(4,6)

(5,6)

(6,6)

There are 6*6=36 possible outcomes. Of these, the following would achieve the result desired:

(1,2)

(1,3)

(1,4)

(1,5)

(1,6)

(2,3)

(2,4)

(2,5)

(2,6)

.

.

.

(5,6)

For the first die equal to 1, there are 5 successful results. For the first die equal to 2, there are 4 successful results....For the first die equal to 5, there is 1 successful result. The total number of successful outcomes=5+4+3+2+1.

So the probability that the desired outcome is obtained=(5+4+3+2+1)/36=15/36=5/12.

The lowest number I can roll on a die is 1.

In ten rolls, that's a minimum of ten; I cannot make it 8 or less.

Zero is a foul throw.

Your question did not identify one distribution in particular. I have provide in the related link the moment generating functions of various probability distributions.

Never. If you roll it 1 time, there can be no "then".

1/2*25/51*24/50*23/49

if cards are not replaced

In the field of IT you are dealing with probabilities all day long. How long will the hardware last, how can you keep the signal for the network strong all over the building, how will adding a new group of computers impact the network, or heaven forbid your network come under attack and you need to keep damage to a minimum while fending off the attack. IT professionals think in probabilities. They're always running scenarios through their heads to come up with and fix problems before they occur.

s